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debangshi das from Springdale High School, Kalyani
Subject :IMO    Class : Class 3

Ans 1:

Darsh Vijay from The Orbis School, Pune
Class : Class 5

Ans 2:

LALIT MANI from K R Mangalam World School, New Delhi
Class : Class 6
how will we solve this?

Ans 3:

Darsh Vijay from The Orbis School, Pune
Class : Class 5

Ans 4:

Riddhiraj Saha from St. Xeviers Institution , Panihati, Kolkata
Class : Class 8
how will i solve this problem?

Ans 5:

LALIT MANI from K R Mangalam World School, New Delhi
Class : Class 6
Got it

Ans 6:

Aryan Goyal from DPS , Dwarka, New Delhi
Class : Class 3
how did you get the answer

Ans 7:

sklogic from SSM School, Chennai
Class : Class 3
Let Janak points = J | Adil A = J + 2 | Rohit R = (9/5) * J | Adil + Janak + Rohit = 59 | A + J + R = 59 | Replace as above | (J + 2) + J + (9/5)*J = 59 | 2J + 2 + 9J/5 = 59 | To remove 5 in denominator, multiply entire equation by 5 | 10J + 10 + 9J = 295 | 19J = 295 - 10 | 19J = 285 | J = 15 | Hence Janak's points = 15 | => Adil = J + 2 = 17 points |

Ans 8:

Sai Lakshmi Rao from Maneckji Cooper Education Trust, Mumbai
Class : Class 4
Shouldnt it be 15? The equation is (X 2) X [(9/5)X] = 59

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debangshi das from Springdale High School, Kalyani
Subject :IMO    Class : Class 3

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debangshi das from Springdale High School, Kalyani
Subject :IMO    Class : Class 3

Ans 1:

Shreyas Singh from Podar International School, Pune
Class : Class 6
B

Ans 2:

Vikram from AVM, Mumbai
Class : Class 5
The way I taught my child was to try with each option, that is, start with option A, assume 40 is the number of soldiers, then calculate no of legs of soldiers, then minus that from total no. of legs, and see if the resulting number gives u the required number of horses you need in order to get a total of 45 horses and soldiers. Repeat the same for option B, C and D. Answer is B. This is how we did it: Assume 35 as no. of soldiers 35x2 = 70 legs of soldiersM Minus 70 from 110 (total legs)= 40 legs 40 horses legs = 40 divided by 4 =10 horses Therefore 35 soldiers and 10 horses = 45 soldiers and horses totally

Ans 3:

Mahesh M G from Surabhi vidyaniketan, Hosapete
Class : Class 3
Explain the answer properly

Ans 4:

Ravi Kumar Tammineni from ,
Class : Class 3
Hey you don't understand

Ans 5:

Shreyas Singh from Podar International School, Pune
Class : Class 6
The answers in options needs to be considered while answering the question. The total number of horses and soldier in the troop is 45. Let us consider option A with 40 soldiers = 80 human legs so the balance legs are 30 which is not possible for horses as they have 4 legs. Going by option B= 35 soldiers = 70 human legs. So the balance legs remains 40, which is possible for 10 horses. Now the total number of horses and soldiers are 45 so 35 soldiers+10 horses = 45 and hence is a right answer. The balance options can be checked in similar way and will be found incorrect.

Ans 6:

Aryan Goyal from DPS , Dwarka, New Delhi
Class : Class 3
it is not a class 3 question understand that

Ans 7:

Sarang Pande from Podar International School, Rajkot
Class : Class 4
The level of the question is certainly not for Class 3. It involves use of simultaneous equations. Answer is 35 soldiers.

Ans 8:

Aryan Goyal from DPS , Dwarka, New Delhi
Class : Class 3

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Daksh from RKC, Rajkot
Subject :IMO    Class : Class 3

Ans 1:

Yash from Dps, Noida
Class : Class 2
solution is (24*5) (48*4)=312hence answer is B

Ans 2:

Anay Bansal from DPS ELDECO , Lucknow
Class : Class 3
D

Ans 3:

AANYA GUPTA from MDPS Faridabad, Faridabad
Class : Class 8
in the question each is missing.. the balls are for each box

Ans 4:

Ayaan Rai Mangla from MRIS, Ludhiana
Class : Class 3
Answer is D as per question

Ans 5:

Rijrashwa Sreejith from Devamatha C M I Public School, Thrissur
Class : Class 4
D

Ans 6:

Shreeda Dewangan from Delhi public school , Raipur
Class : Class 5
correct answer is B

Ans 7:

AKSHAJ SRIVASTAVA from MOUNT LITERA ZEE SCHOOL, Kanpur
Class : Class 9
B312

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Manasmita Dash from B.P.D.A.V, Hyderabad
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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Manasmita Dash from B.P.D.A.V, Hyderabad
Subject :IMO    Class : Class 5

Ans 1:

MUDIT KUMAR GARG from THE CAMBRAGE SCHOOL, DHURI
Class : Class 5
the correct answer is b

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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Manasmita Dash from B.P.D.A.V, Hyderabad
Subject :IMO    Class : Class 5

Ans 1:

Adithya Vardhan from Loyola School, Trivandrum
Class : Class 9
option D 31 since it is a prime number

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Sarah Ishika Dowerah from Delhi Public School, Numaligarh
Subject :IMO    Class : Class 4

Ans 1:

vibhor from S D Vidya Mandir, Panipat
Class : Class 7
C

Ans 2:

Mayank Raj from Litera velly, Patna
Class : Class 4

Ans 3:

aritroray from Chirec International School, Hyderabad
Class : Class 8
3 years = 36 months, and EMI paid each month= 1970/-, so the total amount paid in EMI is 36 x 1970, which is 70920. Therefore, total value of the car is 35000 + 70920 = 105920/-.

Ans 4:

Mayank Raj from Litera velly, Patna
Class : Class 4

Ans 5:

Mayank Raj from Litera velly, Patna
Class : Class 4
3years=36 monthsEMIper month=1970EMI in three year=72920Rajat paid in advance=35000Total amount paid=70920 35000=105920......[C] is the answer............................

Ans 6:

AARAV GULATI from Vivek Summit, New Delhi
Class : Class 4
A- EMI 1970 per month 3 years = 36 months Total Amount Paid in three years 36 x 1970 = 70920 B - Rajat Paid Advance - 35000 Total Amount Paid A +B 70920+35000= 105920 Answer is C

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arnav makani from The Gurukul sector-20, Panchkula
Subject :IMO    Class : Class 6

Ans 1:

Venneti Bhargav from gyan bharati, New Delhi
Class : Class 7
good question

Ans 2:

Pragya Mahajan from BCM Arya Model Sr Sec School, Ludhiana
Class : Class 8
I THINK C. IS NOT THE NET OF THE SOLID

Ans 3:

Rishit Sharma from Nehru World School, Ghaziabad
Class : Class 7
C is the answer of this question

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arnav makani from The Gurukul sector-20, Panchkula
Subject :IMO    Class : Class 6

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