International Maths Olympiad Forum By SOF Olympiad Trainer - Page 669
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Aditi Deo from Thakur International, Mumbai
Subject :IMO    Class : Class 5

Ans 1:

Anshul agarwal from Gear innovative international school, Bengaluru
Class : Class 5
12

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Soundharya from ISWK, Muscat
Class : Class 8
10,000,000,000 hundreds are there in 1 trillion

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Aditi Deo from Thakur International, Mumbai
Subject :IMO    Class : Class 5

Ans 1:

Pranav Arun from garib school, Mumbai
Class : Class 8
you are absoulutely wrong imagine how many computers will be needed suppose you are not able to finish the paper on time teachers give you extra time you may come across my fate last year 2nd level i had 3 ques left in achiever's section and the person snatched my paper they had only given us 45 mins and then when i saw the result i got 34 out of 40 i may have come world no. 1 very bad school management

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John Calvin from vaels billabong, kottiwakkam
Subject :IMO    Class : Class 1

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Aarush Semwal from DPS Noida, Noida
Class : Class 4
sorry, 159 because a+b=27 b-a=9. Therefore a=18 b=9. d-c=3 and a+b+c+d=36 ab=27 so 36-27=9 d is bigger than c so d=6 c=3 a=18 b=9 c=3 d=6 final question a*b+c-d 18*9= 162 162+3=165 165-d or 165-6=159 ANSWER=159

Ans 2:

Jedidiah Asriel from Emerald Valley Public School, Salem
Class : Class 10
I find this question too high for Class 1. Anyway, I'll answer this. Given that a+b=27; b-a=9; a+b+c+d=36. Substituting a+b=27 in a+b+c+d=36, 27+c+d=36-27=9. c+d=9; d-c=3. Adding a+b and b-a, a+b+b-a=27+9, 2b=36, b=18. Therefore a=27-18=9. Adding c+d and d-c, c+d+d-c=9+3, 2d=12, d=6. Therefore c=6-3=3. Now, a=9; b=18; c=3; d=6. a*b+c-d = 9*18+3-6 = 162+3-6 = 165-6 = 159. Answer: 159

Ans 3:

Aarush Semwal from DPS Noida, Noida
Class : Class 4
114

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aditya from carmel convent high school, badlapur
Subject :IMO    Class : Class 10

Ans 1:

adrijab from DELHI PUBLIC SCHOOL, PANIPAT REFINERY, Panipat
Class : Class 9
the answer is 50.5. it can be solved by :sum of the nos./no. of numbers. by formula, sum of first 100 natural nos. is n*(n+1)/2=100*101/2=5050. so answer comes out to be 5050/100=50.5

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AMAN SAIKIA from DPS Duliajan, DULIAJAN
Subject :IMO    Class : Class 5

Ans 1:

Meowness from Why should I tell?, Wow
Class : Class 5
It was a mathematical calculation created by Pythagoras, to find out the hypotenuse of a right angled triangle. It is -: Altitude[squared]+ Base[squared]= Hypotenuse[squared]

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Samya Saha from Ramakrishna mission Vidyalaya Narendrapur, Burdwan
Subject :IMO    Class : Class 7

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Ananyo Sen from Ramakrishna Mission Vidyalaya Narendrapur , Asansol
Class : Class 8
Median is a middle no if a sequence.

Ans 2:

Steve Nathan Desa from The Rosary High School, Merces
Class : Class 7
when u arrange the numbers in number wise and select the middle number(eg- Q-1155627..... A-1125567 Therefore MEDIAN= 5 )

Ans 3:

user from St Peters School, Bengaluru
Class : Class 7
Median is the middle term in a sequence of ascending ordered numbers.

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G. Priyanka from Chennai Public School, Chennai
Subject :IMO    Class : Class 7

Ans 1:

Samya Saha from Ramakrishna mission Vidyalaya Narendrapur, Burdwan
Class : Class 8
If the question is :- "in the figure (not drawn to scale), ABCD is a rectangle, FA = FG, AGE and BGF are straight lines. find x+y." then the answer is:- angle DAF is 20 degree, angle ADF is 90 degree, so, angle DFA = 180-(20+90) =70 degree. as DFC and AB are parallel, angle DFA = angle FAB =70 degree DA and CEB are parallel so, angle BEA = angle EAD = 74 degree so, angle FAG =74 - 20 =54 degree as FAG is a isoseles triangle, angle FAG = angle FGA = 54 degree so x = 180 -(54+54) degree =72 degree again, angle AGF= angle BGE = 54 degree so, y = 180 - ( 74 + 54 ) = 180 - 128 =52 degree as a result ( x + y ) = 72 + 52 =124 degree (option B). THANK YOU

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Raju Pal from sunflag school, maharastra
Subject :IMO    Class : Class 7

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SUBODH KUMAR from Delhi Public School, Bokaro
Subject :IMO    Class : Class 6

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G. Priyanka from Chennai Public School, Chennai
Subject :IMO    Class : Class 7

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Pulkit mittal from GAIL DAV PUBLIC SCHOOL, AURAIYA
Class : Class 9
13 OF DEC

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