Subject :IMO Class : Class 5
Subject :IMO Class : Class 5
Ans 1:
Class : Class 8
you are absoulutely wrong imagine how many computers will be needed suppose you are not able to finish the paper on time teachers give you extra time you may come across my fate last year 2nd level i had 3 ques left in achiever's section and the person snatched my paper they had only given us 45 mins and then when i saw the result i got 34 out of 40 i may have come world no. 1 very bad school management
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Subject :IMO Class : Class 1
Ans 1:
Class : Class 4
sorry, 159 because a+b=27 b-a=9. Therefore a=18 b=9. d-c=3 and a+b+c+d=36 ab=27 so 36-27=9 d is bigger than c so d=6 c=3
a=18
b=9
c=3
d=6
final question a*b+c-d
18*9= 162
162+3=165
165-d or 165-6=159
ANSWER=159
Ans 2:
Class : Class 10
I find this question too high for Class 1. Anyway, I'll answer this.
Given that a+b=27; b-a=9; a+b+c+d=36. Substituting a+b=27 in a+b+c+d=36, 27+c+d=36-27=9. c+d=9; d-c=3.
Adding a+b and b-a, a+b+b-a=27+9, 2b=36, b=18. Therefore a=27-18=9.
Adding c+d and d-c, c+d+d-c=9+3, 2d=12, d=6. Therefore c=6-3=3.
Now, a=9; b=18; c=3; d=6.
a*b+c-d = 9*18+3-6 = 162+3-6 = 165-6 = 159.
Answer: 159
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Subject :IMO Class : Class 10
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Subject :IMO Class : Class 5
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Subject :IMO Class : Class 7
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Subject :IMO Class : Class 7
Ans 1:
Class : Class 8
If the question is :-
"in the figure (not drawn to scale), ABCD is a rectangle, FA = FG, AGE and BGF are straight lines. find x+y."
then the answer is:-
angle DAF is 20 degree,
angle ADF is 90 degree,
so, angle DFA = 180-(20+90)
=70 degree.
as DFC and AB are parallel,
angle DFA = angle FAB =70 degree
DA and CEB are parallel
so, angle BEA = angle EAD = 74 degree
so, angle FAG =74 - 20 =54 degree
as FAG is a isoseles triangle, angle FAG = angle FGA = 54 degree
so x = 180 -(54+54) degree
=72 degree
again, angle AGF= angle BGE = 54 degree
so, y = 180 - ( 74 + 54 )
= 180 - 128
=52 degree
as a result ( x + y ) = 72 + 52 =124 degree (option B).
THANK YOU
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Subject :IMO Class : Class 7
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 7