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Aviral Shukla from Apeejay School Sheikh Sarai, New Delhi
Subject :IMO    Class : Class 4

Ans 1:

JESHAL MOHAPATRA from GEMS MODERN ACADEMY, Dubai
Class : Class 4
missing is 9cm and 18cm which goes accoording to D!

Ans 2:

Aaditya Kant from DPS, Nerul, Navi Mumbai
Class : Class 4
d

Ans 3:

Shreeraj from ISWK, Muscat, Muscat
Class : Class 4
Option D

Ans 4:

Snow White from Le Setea , Paris
Class : Class 4
The answer is D

Ans 5:

Ira Agrawal from Sancta Maria International School, Hyderabad
Class : Class 3
It’s obviously D!!!

Ans 6:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Answer is D as the question says to find the perimeter, which is (7*2) cm+4 cm+(9*2) cm+15 cm+8 cm+5 cm+(4+5+9) cm=14 cm+4 cm+18 cm+15 cm+8 cm+5 cm+18 cm=82 cm.

Ans 7:

Deepayan Das from South Point School, Kolkata
Class : Class 5
oh! yeah it's D

Ans 8:

Arya Prabhughate from Narayana E Techno School, NALASOPARA
Class : Class 5
ans is d

Ans 9:

ikshika kumar from MVN SCHOOL, FARIDABAD
Class : Class 4
D) 82 cm

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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Kabir Bajaj from P G Garodia School ICSE, Mumbai
Subject :IMO    Class : Class 3

Ans 1:

saina from dps, INDIRAPURAM
Class : Class 2

Ans 2:

Darshini Chakravarty from Pinnacle High International School, Mumbai
Class : Class 4

Ans 3: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

Ans 1:

Rgdn from SDIS, Gandhinagar
Class : Class 8
Answer is C. a^2 ÷ 2 Because diagonals of a square are equal. And area of rhombus formula can be used here because both have all sides equal. Area of rhombus= 1/2(diagonal 1 × diagonal 2) Because diagonals are equal, we write it as : a × a÷ 2 =a^2 ÷2

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Shantanu P Yadav from ST. Vincent Pallotti Nagpur, Nagpur
Subject :IMO    Class : Class 6

Ans 1:

pranjal kaur from SVISG, DELHI
Class : Class 6
option B

Ans 2:

Nisarg Milan Salot from Narayana E-Techno School, Mumbai
Class : Class 8
option B

Ans 3:

from ,
Class :
B: New number is smaller than original number.

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Aadithya John Gejo from Airforce school AV camp, Bangalore
Subject :IMO    Class : Class 4

Ans 1:

Dhanshree from Sunshine school, Karanja
Class : Class 4
The answer is C

Ans 2:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Answer is C as the question says 3098+1427<5420+2018 and we have to find how much less 3098+1427<5420+2018, which is 5420+2018-3098+1427 and to get this we have to follow the BODMAS rule, which is 7438-4525=2913.

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amol dewale from ,
Subject :IMO    Class : Class 7

Ans 1:

from DPS R.K. PURAM,
Class : Class 9
D

Ans 2:

Keshav from RPS , Mahendergarh
Class : Class 7
B

Ans 3:

Rishit Jain from Dps, Meeru5
Class : Class 10
Ans is d 20

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Achintya k j from KENDRIYA VIDYALAYA GOLE MARKET, NEW DELHI
Subject :IMO    Class : Class 7

Ans 1:

Keshav from RPS , Mahendergarh
Class : Class 7
D

Ans 2:

from , Kolkata
Class : Class 9
Angle BAC = x + 40 - x => 40 As triangle ABC is an isosceles triangle with AB = AC, angle acb = angle abc = x Therefore, as angle abc + angle acb + angle bac = 180 then, x + x + 40 = 180 =>2x = 180 - 40 =>2x = 140 =>x = 70

Ans 3:

from DPS R.K. PURAM,
Class : Class 9
d

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from , Kolkata
Subject :IMO    Class : Class 7

Ans 1:

Nilanjana De from Delhi Public School North, Bengaluru
Class : Class 8
Since triangle ABD is congruent to triangle ACD by SSS rule, so the altitude will also be the same. Which means BE=EC, as these are the altitudes of the triangles.

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