International Maths Olympiad Forum By SOF Olympiad Trainer - Page 293

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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 7
A is Answer

Ans 2:

Class : Class 7
A is Answer

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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 8

Ans 2:

Class : Class 7
answer is 1/2

Ans 3:

Class : Class 10
YES,ANSWER IS 1/2

Ans 4:

Class : Class 7
Answer should be 1/2.

Ans 5:

Class : Class 7
the answer is 3/4 because there are 4 possibilities - heads

Ans 6:

Class : Class 7

Ans 7:

Class : Class 8
Even I think the answer should be 1/2

Ans 8:

Class : Class 8
The answer must be 1/2in two coins there are total 4 possibilities of head n tailout of which 2 possibilities are of tail hence it'll be 2/4 which is equal to 1/2

Ans 9:

Class : Class 8
1/2

Ans 10:

Class : Class 7
Answer should be 1/2

Ans 11:

Class : Class 10

Ans 12:

Class : Class 9
The answer should be B since getting at least one tail has a probability of 2/4 and simplifying it we will get 1/2

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Subject :IMO    Class : Class 7

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 8
B

Ans 2:

Class : Class 5
B is the answer

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Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
Answer is c

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6

Ans 2:

Class : Class 6
5/15+5/15+1/15=11/15 2/15+4/15+5/15=11/15 1/15+8/15+2/15=11/15 So the answer is D

Ans 3:

Class : Class 8
Answer is d

Ans 4:

Class : Class 6
The correct answer is D

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Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Class : Class 1

(B): Total number of packets bought in March and April = 183
Total number of days in March and April  = 31 + 30 = 61
Packet bought on one day  = Total packets ÷ total days = 183 ÷ 61 = 3
Total packets bought in March =  3 × 31 = 93


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