International Maths Olympiad Forum By SOF Olympiad Trainer - Page 592
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AARAV GULATI from Vivek Summit, New Delhi
Subject :IMO    Class : Class 4

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Kushal from Chirec, Hyderabad
Class : Class 7
28

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AARAV GULATI from Vivek Summit, New Delhi
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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vedant panchal from hiranandani foundation school, Mumbai
Subject :IMO    Class : Class 7

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Rajendra Singvi from SHGS, Nandurbar
Subject :IMO    Class : Class 7

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poonam from army public school, ramgarh cantt
Class : Class 7
correct answer is c. because every multiple of a number is equal to or greater than that

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Rajendra Singvi from SHGS, Nandurbar
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
We have to find out the numbers which can factorize 75 They are 1,3,5,15,25,75.

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Rajendra Singvi from SHGS, Nandurbar
Subject :IMO    Class : Class 7

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Parijat Goyal from THE INDIAN SCHOOL, New Delhi
Class : Class 10
(m) as you can see their num. value of each alphabet.....a=1. c=3, e=5, i=9, m=14, n=15, o=16, p=17, r=19, s= 21 Thus m is the 5th one

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PARTH SETHI from DPS Noida, New Delhi
Subject :IMO    Class : Class 5

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Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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Ethan Roche from rcis dahisar, Mumbai
Subject :IMO    Class : Class 7

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Ashutosh Shrivastava from Campion School, Bhopal
Class : Class 7
In other options, HCF is 3

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AARAV GULATI from Vivek Summit, New Delhi
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

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Rajendra Singvi from SHGS, Nandurbar
Subject :IMO    Class : Class 7

Ans 1:

Ashutosh Shrivastava from Campion School, Bhopal
Class : Class 7
Let number be Z. Then 9Z/5=45 so Z=45 X 5 / 9 Z= 25 Now 25 X 1/5 =5 So ans is A

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