International Maths Olympiad Forum By SOF Olympiad Trainer - Page 495

User Forum

Subject :IMO    Class : Class 4

Post Your Answer

Subject :IMO    Class : Class 4

Post Your Answer

Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
D)

Ans 2:

Class : Class 5

Ans 3:

Class : Class 6

Ans 4:

Class : Class 10
It should be 1 not 2 because half half = 1

Ans 5:

Class : Class 5
IT SHOULD BE 21 SQUARE 1/2 SQUARE 1/2 SQUARE

Ans 6:

Class : Class 7
IT SHOULD BE 1 NOT 2. 1/2 1/2 = 1

Ans 7:

Class : Class 5
it makes no sense

Ans 8:

Class : Class 5
It has no sense

Post Your Answer

Subject :IMO    Class : Class 8

Ans 1:

Class : Class 9

Ans 2:

Class : Class 8
How can they give they two same options and mark one wrong

Ans 3:

Class : Class 9
It's a mistake both options are right

Ans 4:

Class : Class 4
B and D are identical It's a mistake both options are right

Ans 5:

Class : Class 8
B and D are identical

Ans 6:

Class : Class 9
its not fair if we mark option d then they say correct answer is option b and if we mark option b then they say that option d is the correct answer.

Ans 7:

Class : Class 9
answer is both B and D

Post Your Answer

Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
it is very simple and can be solved with Pythagoras.Length=2y Breadth=yroot of [(2y)square ysquare]=9 x root of 5root of [4ysquare ysquare]=9 x root of 5root of 5ysquare=9 x root of 5 = y x root of 5thus y = 9 and 2y = 18p=54

Ans 2:

Class : Class 6

Ans 3:

Class : Class 9
give explanation please.

Ans 4:

Class : Class 7
First of all,diagonal of a rectanhle=square root of l^2 b^2,so 9×square root of 5 is square root of 81 × 5 that is 405 so here 2x is l and x is b.if i m taking l is 18 and b is 9 and squaring them we get 405 so perimeter of the rectangle is 2(18 9) that is 54.

Ans 5:

Class : Class 8
pl give solution, very confusing question

Ans 6:

Class : Class 7
w=xl=2xd=9root52(l b)=?2(x 2x)=?using pythogras theorem,xsquare 4 x square=(9root5)squared5xsquare=405x square=81x=9hence substitute values with x,perimeter=54

Ans 7:

Class : Class 9
This can be solved like this: take length as 2x and breadth as x. Applying the pythagoras theorem, (x)^2 (2x)^2 = (9 * root 5)^2. Equal to x squared 4x squared = 9 squared * root 5 squared 5x squared = 81 * 5. 5 and 5 cancel on both sides. x squared = 81 x = 9 = breadth 2x = 18 = length perimeter = 2 (l b) 2 * 27 = 54

Ans 8:

Class : Class 9
explaination of answer not provide....how to check the solution??

Ans 9:

Class : Class 7
please provide explanation soon

Ans 10:

Class : Class 7
Sorry diagonal of a rectangle is l^2 b^2

Post Your Answer

Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
C)

Ans 2:

Class : Class 6
C)

Post Your Answer

Subject :IMO    Class : Class 6

Ans 1:

Class : Class 7

Ans 2:

Class : Class 6
Answer is a

Ans 3:

Class : Class 6

Post Your Answer

Subject :IMO    Class : Class 6

Post Your Answer

Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4

Ans 2:

Class : Class 8

Ans 3:

Class : Class 4
D

Ans 4:

Class : Class 8
c

Post Your Answer

Subject :IMO    Class : Class 6

Ans 1:

Class : Class 5
is this answer correct ?what is the answer.....correct or no

Ans 2:

Class : Class 10
the answer should be equilateralbecause we have studied everywhere that two equilateral triangle(with same length) are kept such as there one side of both the triangle are adjacent , is a square

Ans 3:

Class : Class 9

Ans 4:

Class : Class 6

Ans 5:

Class : Class 8
I don't think the answer is correct

Post Your Answer