Subject :IMO Class : Class 4
Subject :IMO Class : Class 3
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 8
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Subject :IMO Class : Class 5
Ans 1: (Master Answer)
Class : Class 1
(A): The number of balls and chocolates Rahul gave to each of his friends = (8 ÷ 4) + (16 ÷ 4)
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Subject :IMO Class : Class 6
State 'T' for true and 'F' for false and select the correct option.
(i) Fractions can never be reduced to lowest form.
(ii) The shaded fraction in 
is 
.
(iii) The set of fractions 
| (i) | (ii) | (iii) | |
|---|---|---|---|
| A | T | F | F |
| B | T | T | F |
| C | F | T | F |
| D | F | F | T |
Ans 1:
Class : Class 6
Ans 2:
Class : Class 6
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Subject :IMO Class : Class 8
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Subject :IMO Class : Class 8
Fill in the blanks.
(i) The solution of the equation ax + b = 0 is_______.
(ii) The shifting of a number from one side of an equation to other is _______.
(iii) If a and b are positive integers then the solution of the equation ax = b has to be always _______.
(iv) Linear equation in one variable has only one variable with power _______.
| (i) | (ii) | (iii) | (iv) | |
| A | x = b/a | commutativity | positive | 1 |
| B | x = –b/a | commutativity | negative | 2 |
| C | x = b/a | transposition | negative | 2 |
| D | x = –b/a | transposition | positive | 1 |
Ans 1: (Master Answer)
Class : Class 1
(D): (i) We have, ax + b = 0
⇒ ax = – b
(ii) The shifting of a number from one side of an equation to other is called transposition.
(iii) We have, ax = b
⇒ 
which is the required solution
Given that a and b are positive integers.
∴ Solution of the equation ax = b has to be always positive.
(iv) Linear equation is of the form ax + b = 0 i.e., only one variable with power 1.
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Subject :IMO Class : Class 4
Ans 1:
Class : Class 4
The answer of this question is option [B].
Ans 2:
Class : Class 5
B is the answer