International Maths Olympiad Forum By SOF Olympiad Trainer

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Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 3
the answer is six because 10-4

Class : Class 3
answer is 4

## Ans 3:

Class : Class 3
correct answer is 4

## Ans 4:

Class : Class 3
CORRECT Answer is 4

## Ans 5:

Class : Class 3
But its answer is 4

## Ans 6:

Class : Class 3
yes answer is 4 from Mokshada sikachi

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Subject :IMO    Class : Class 4

Class : Class 4

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Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 5
Ans is B because 3645279+2153467=5798746. 5798746 will be rounded to its nearest ten thousand, which is 5800000, since 98746 will be rounded to nearest ten thousand, which is 100000, 1 will be carried to the lakhs place, or, you can say that 3645279 and 2153467 will be rounded to the nearest ten thousand, which will be 3650000 and 2150000, respectively. 3650000+2150000=5800000.

Class : Class 5
Option B)

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Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Class : Class 8

## Ans 3:

Class : Class 4
isn't the answer "A"

Class : Class 8
the answer is 7.

Class : Class 8

## Ans 6:

Class : Class 6
the solution of the equation is 3*3*5*5*5*2*7 which has seven prime factors

## Ans 7:

Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

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Subject :IMO    Class : Class 3

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Subject :IMO    Class : Class 3

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Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 2
100 tens = 1 thousand

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Subject :IMO    Class : Class 8

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Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 7
its more than easy D

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Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 3
correct answer should be 33

Class : Class 3
Out of Syllabus

## Ans 3:

Class : Class 3
I don't know the answer because IT IS OUT OF SYLLABUS

## Ans 4:

Class : Class 3
it is a little tricky but i solved it.

Class : Class 4
out of syallabus

## Ans 6:

Class : Class 4
the answer is 108

## Ans 7:

Class : Class 4
It is NOT out of syllabus . The sulution is that one moon is 18.So,18x18=324.To get the star devide 18 by 3=6.18-6=12

## Ans 8:

Class : Class 4
IT IS OUT OF SYLLABUS.

Class : Class 3

## Ans 10:

Class : Class 3
options given seems to be wrong

Class : Class 3