Post Your Answer
Post Your Answer
Post Your Answer
Post Your Answer
In the given figure (not drawn to scale), AD is parallel to BC. JDK, GHCI, EABF are straight and parallel lines.
Find:
(i) ∠GHD – ∠HDC (ii) ∠BCI + ∠HAB.
(i) | (ii) | |
A | 58° | 150° |
B | 48° | 150° |
C | 58° | 180° |
D | 48° | 180° |