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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
Does the answer come in point???

Ans 2:

Class : Class 8
COMPUTER will be coded as RETUPMOC.

Ans 3:

Class : Class 6
retupmoc

Ans 4:

Class : Class 10
RETUPOMC

Ans 5:

Class : Class 6
The answer is TERUPMOC

Ans 6:

Class : Class 7
RETUPMOC

Ans 7:

Class : Class 5
RETUPMOC is the answer

Ans 8:

Class : Class 6
Thankyou for helping.

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 8
10,000,000,000 hundreds are there in 1 trillion

Ans 2:

Class : Class 5
12

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 8
you are absoulutely wrong imagine how many computers will be needed suppose you are not able to finish the paper on time teachers give you extra time you may come across my fate last year 2nd level i had 3 ques left in achiever's section and the person snatched my paper they had only given us 45 mins and then when i saw the result i got 34 out of 40 i may have come world no. 1 very bad school management

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Subject :IMO    Class : Class 1

Ans 1:

Class : Class 4
114

Ans 2:

Class : Class 10
I find this question too high for Class 1. Anyway, I'll answer this. Given that a+b=27; b-a=9; a+b+c+d=36. Substituting a+b=27 in a+b+c+d=36, 27+c+d=36-27=9. c+d=9; d-c=3. Adding a+b and b-a, a+b+b-a=27+9, 2b=36, b=18. Therefore a=27-18=9. Adding c+d and d-c, c+d+d-c=9+3, 2d=12, d=6. Therefore c=6-3=3. Now, a=9; b=18; c=3; d=6. a*b+c-d = 9*18+3-6 = 162+3-6 = 165-6 = 159. Answer: 159

Ans 3:

Class : Class 4
sorry, 159 because a+b=27 b-a=9. Therefore a=18 b=9. d-c=3 and a+b+c+d=36 ab=27 so 36-27=9 d is bigger than c so d=6 c=3 a=18 b=9 c=3 d=6 final question a*b+c-d 18*9= 162 162+3=165 165-d or 165-6=159 ANSWER=159

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Subject :IMO    Class : Class 10

Ans 1:

Class : Class 9
the answer is 50.5. it can be solved by :sum of the nos./no. of numbers. by formula, sum of first 100 natural nos. is n*(n+1)/2=100*101/2=5050. so answer comes out to be 5050/100=50.5

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5
It was a mathematical calculation created by Pythagoras, to find out the hypotenuse of a right angled triangle. It is -: Altitude[squared]+ Base[squared]= Hypotenuse[squared]

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
Median is the middle term in a sequence of ascending ordered numbers.

Ans 2:

Class : Class 7
when u arrange the numbers in number wise and select the middle number(eg- Q-1155627..... A-1125567 Therefore MEDIAN= 5 )

Ans 3:

Class : Class 8
Median is a middle no if a sequence.

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 8
If the question is :- "in the figure (not drawn to scale), ABCD is a rectangle, FA = FG, AGE and BGF are straight lines. find x+y." then the answer is:- angle DAF is 20 degree, angle ADF is 90 degree, so, angle DFA = 180-(20+90) =70 degree. as DFC and AB are parallel, angle DFA = angle FAB =70 degree DA and CEB are parallel so, angle BEA = angle EAD = 74 degree so, angle FAG =74 - 20 =54 degree as FAG is a isoseles triangle, angle FAG = angle FGA = 54 degree so x = 180 -(54+54) degree =72 degree again, angle AGF= angle BGE = 54 degree so, y = 180 - ( 74 + 54 ) = 180 - 128 =52 degree as a result ( x + y ) = 72 + 52 =124 degree (option B). THANK YOU

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Subject :IMO    Class : Class 7

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