Ans 1:
Class : Class 8
Let tom has Rs. X
Let Jasmine has Rs y
A.T.Q
x+y = 41
x = 41-y
1/4 * x = 2 + 1/7*y
1/4*(41-y) = 2 + 1/7*y
41/4 - y/4 = 2 + y/7
41/4 - 2 = y/7 + y/4
33/4 = 11y/28
33/4*28/11 = y
21 = y
x+21=41
X = 41-21 = 20
Ans 2:
Class : Class 8
Tom and jasmine have Rs 41 altogether .
let,
Jasmine has Rs x..
therefore tom has Rs( 41-x) {the rest of the money}
according to the question,
1/4 of Tom's money is 2 more than 1/7 of jasmine's money.
therefore,
1/4 x (41-X) = (1/7 x X)+2
or, ( 41-X)/4=X/7+2
or, (41-X)/4=(X+14)/7
or; (7x41)-7X=4X+(4x14)
or; 287-7X=4X+56
or; 287-56=4X+7X
or, 231=11X: 11X=231
X=231/11 =21 THE ANSWER IS 21 OR TOM HAS RS 21................
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Ans 1:
Class : Class 10
There exist two such numbers : (1-sqrt(5))/2 and (1+sqrt(5))/2
This can be taken out by making a quadratic equation and using the discriminant formula,
which is:
x=(b*sqrt(b^2-4ac))/2a
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Ans 1:
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Ans 1:
Ans 2:
Class : Class 8
Yes, because of the simple reason, that other polygons have edges! Circle has the same distance from the center at each and every point, whereas the distance from the center to the edges is generally lesser than that to the vertices in other polygons Thus, more area is covered in case of circles.
