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Ans 8:
Class : Class 10
Longer side of the rectangle paper = 7 + 6 + 4 + 4 + 4 = 25 cm
Smaller side of the rectangle paper = 4 cm
Total length (perimeter) = 25 + 25 + 4 + 4 = 58 cm
Smaller side of the rectangle paper = 4 cm
Total length (perimeter) = 25 + 25 + 4 + 4 = 58 cm
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Ans 1:
Class : Class 9
(a^2-b^2)/ab - (ab-b^2)/(ab- a^2)
#Using special product
= (a+b)(a-b)/ab - (ab-b^2)/(ab- a^2)
#Removing out a and b common
= (a+b)(a-b)/ab - b(a-b)/a(b-a)
#LCM of both denominators i.e. ab and a(b-a) is ab(b-a)
#Hence we multiply first equation by (b-a) and second equation by b
= (a+b)(a-b)(b-a)/ab(b-a) - b^2(a-b)/ab(b-a)
#Taking the denominator common
= [(a+b)(a-b)(b-a) - b^2(a-b)]/ab(b-a)
#Taking (b-a) common in the numerator
=[(b-a)(a^2-b^2-b^2)]/ab(b-a)
#Cancelling out (b-a) from numerator and denominator
=a^2 - 2 b^2 / ab
Hence B is the answer.
Ans 2:
Class : Class 9
(a^2-b^2)/ab - (ab-b^2)/(ab- a^2)
#Using special product
= (a+b)(a-b)/ab - (ab-b^2)/(ab- a^2)
#Removing out a and b common
= (a+b)(a-b)/ab - b(a-b)/a(b-a)
#LCM of both denominators i.e. ab and a(b-a) is ab(b-a)
#Hence we multiply first equation by (b-a) and second equation by b
= (a+b)(a-b)(b-a)/ab(b-a) - b^2(a-b)/ab(b-a)
#Taking the denominator common
= [(a+b)(a-b)(b-a) - b^2(a-b)]/ab(b-a)
#Taking (b-a) common in the numerator
=[(b-a)(a^2-b^2-b^2)]/ab(b-a)
#Cancelling out (b-a) from numerator and denominator
=a^2 - 2 b^2 / ab
Hence B is the answer.