International Maths Olympiad Forum By SOF Olympiad Trainer - Page 296

User Forum

Subject :IMO    Class : Class 6

Ans 1:

Class : Class 9
x = 2k/3 and Y = 8k/5Therefore, x : y= x/y = (2k/3)/(8k/5)= (2k/3) *(5/8k)On cancelling, 2k with 8k, we get= (1/3) * (5/4) = 5/12Thus, x:y = 5:12Answer - (C)

Ans 2:

Class : Class 6

Ans 3:

Class : Class 7

Ans 4:

Class : Class 9

Post Your Answer

Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
Subtract the number of females from whole population. :)

Ans 2:

Class : Class 8
Everybody knows this

Ans 3:

Class : Class 6
Solved in 15 seconds. It was so easy! ;)

Ans 4:

Class : Class 7
So Easy!

Ans 5:

Class : Class 6
Yup !

Post Your Answer

Subject :IMO    Class : Class 6

Post Your Answer

Subject :IMO    Class : Class 5

Ans 1:

Class : Class 8
6th multiple of 7 = 4210th multiple of 7 = 7042 - 70 = 2828* 2 = 56So, the correct answer is B.

Ans 2:

Class : Class 5

Ans 3:

Class : Class 1
Ans 1 I think u have copied this from the solution. This is the same thing in the solution. No offence.

Ans 4: (Master Answer)

Class : Class 1

(B): 6th multiple of 7 = 42
10th multiple of 7 = 70
Now,  = 2 × (70 - 42) = 2 × 28 = 56


Ans 5:

Class : Class 1
And I did not understand the solution. So, can u explain it better?

Post Your Answer

Subject :IMO    Class : Class 9

Ans 1:

Class : Class 8

Ans 2: (Master Answer)

Class : Class 1

(D): Division of any two integers is not always an integer.


Post Your Answer

Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Class : Class 1

(D): Time clock showing = 5:10
Since its 5 minutes slower, actual time = 5:15
Rahul went out to play at 5:15, and came back after 25 minutes
Actual time he came back = 5:40 p.m.
 


Post Your Answer

Subject :IMO    Class : Class 7

Ans 1:

Class : Class 8
No, it's answer B.. I would suggest you to take numeric values for a, b, c and d.. Then u will get to know the answer..

Ans 2:

Class : Class 7
what if we keep the values of a = 4, b = 8, c = 1, d = 2 . and now try

Post Your Answer

Subject :IMO    Class : Class 6

Post Your Answer

Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Class : Class 1

(C):Number of boxes = 8

Number of sweets in 1 box = 26
Number of sweets in 8 boxes = 26 x 8 = 208
Cost of 1 sweet = Rs 5
Cost of 208 sweets = 208 x 5 = Rs 1040


Post Your Answer

Subject :IMO    Class : Class 8

Ans 1:

Class : Class 8

Ans 2:

Class : Class 9

Ans 3:

Class : Class 8

Post Your Answer