International Maths Olympiad Forum By SOF Olympiad Trainer - Page 327
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Samiha Grewal from Sat Paul Mittal School, Ludhiana
Subject :IMO    Class : Class 3

Ans 1:

Nihira Tiwari from Delhi public school electronic city, Bengaluru
Class : Class 6

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(D): To tip the scale below to the right, the weight of chocolates should be greater than 37kg.
Weight of 5 chocolates = 5 x 7 = 35kg
Weight of 6 chocolates = 6 x 7 = 42kg
 As, 42kg > 37kg
So, minimum number of chocolates needed = 6


Ans 3:

Nihira Tiwari from Delhi public school electronic city, Bengaluru
Class : Class 6
Seee

Ans 4:

ANIMESH BEHERA from TIMPANY, VISAKHAPATTNAM
Class : Class 3
(D):To tip the scale below to the right,the weight ofchocolates should be greater than 37kg.Weight of 5 chocolates =5 x 7=35kgWeight of 6 chocolates=6x7=42kgSo,minimum number of chocolates needed = 6

Ans 5:

Ankit from Delhi Public School Megacity Kolkata, KOLKATA
Class : Class 5

Ans 6:

Nihira Tiwari from Delhi public school electronic city, Bengaluru
Class : Class 6
This question is wrong as 7x9 is 63 and that is also bigger than 37.

Ans 7:

Vivaan Nigam from New Horizon Gurukul, Bangalore
Class : Class 3
its 7

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Nakul Bhasker from National Public School Whitefield, Bangalore
Subject :IMO    Class : Class 4

Ans 1:

Sourish from bgs nps, banglore
Class : Class 8
not very difficult

Ans 2:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5
a

Ans 3:

Nakul Bhasker from National Public School Whitefield, Bangalore
Class : Class 5

Ans 4:

Nakul Bhasker from National Public School Whitefield, Bangalore
Class : Class 5

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Soumyajit Roy from Delhi Public School Jamnagar, Jamnagar
Subject :IMO    Class : Class 7

Ans 1:

Ambar and Adwita from Suncity School, Gurgaon
Class : Class 8

Ans 2:

Arsh Gupta from Cambridge International School, Jalandhar
Class : Class 4

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Yash Bindal from Global Indian International School, Singapore
Subject :IMO    Class : Class 9

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Souraj Saigovindh from Sri chaitanya Techno school, Tirupur
Subject :IMO    Class : Class 7

A number consists of two digits whose sum is 9. If 27 is added to the number, its digits are interchanged. Which of the given steps is CORRECT to find the number?
Step 1 :Let the unit’s digit be x
Step 2 :Then, ten’s digit = (9 – x)
∴ Number = 10 × (9 – x) + x
⇒ 90 – 10x + x = (90 – 9x)
Step 3 :Adding 27 to the number 90 – 9x, we get 117 – 9x
Step 4 :Number with digits interchanged is 10x + (9 – x) = 9x + 9
Step 5 :117 – 9x = 9x + 9
Step 6 :Therefore unit’s digit = 6 and ten’s digit = 3
Step 7 :Hence the number = 36.

A Only Step 4
B Both Step 1 and Step 2
C Step 1, 2, 3 and 4
D All steps are correct


how to find the solution

Ans 1:

Nitin from CHSV, Chennai
Class : Class 6
*x 3=y

Ans 2:

Nitin from CHSV, Chennai
Class : Class 6

Ans 3:

ARUNAV from DPS VINDHYANAGAR, VINDHYANAGAR
Class : Class 9
Nitin , I think you forgot that the sum of the digits of a number should be 9 , As in teh question. All teh other nummbers given by you except 36 is wrong because their digits do nto sum up to 9

Ans 4:

Himanshi Singh from BBPS, Gadarwara
Class : Class 8
Correct answer is D.

Ans 5:

Nitin from CHSV, Chennai
Class : Class 6
The space means addition

Ans 6:

Deepa Jewalkar from Meridian , Hyderabad
Class : Class 7

Ans 7:

Nitin from CHSV, Chennai
Class : Class 6
The number is not only 36 (It is a number , but there are other numbers) . If you keep x as the ten's digit of the original number and y as the unit's digit of the number , any number following : x 3=y , will follow this rule .The numbers following this rule is 14 27=41 , 25 27=52 , 36 27=63 , 47 27=74 , 58 27=85 , 69 27=96 .

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Aaryaman Pradhan from De paul School , Berhampur
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):

(a) Total number of books in both  the libraries = 284683 + 371805
= 656488

(b) Number of more books in second library than the  first library = 371805 - 284683
= 87122


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Asmi Raniga from Indian school Ghubra, Muscat
Subject :IMO    Class : Class 5

Ans 1:

Pranjal from MVN Sector 88, Faridabad
Class : Class 5

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(C): Quantity of syrup Mrs. Preeti had = 5 litres = 5000 ml

Quantity of Syrup she poured in each bottle = 300 ml

Number of bottles needed = 5000 ÷ 300 = 16.67
Therefore, 17 bottles are needed. 


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Aarush Pandya from Inventure Academy, Bangalore
Subject :IMO    Class : Class 2

Study the timings of daily activities of Payal as shown in the table and fill in the blanks.

• Activities that last for 1 hour in total are ___P___ and ___Q___.
• The activity that lasted for 15 minutes only is ___R___.

AP-Reading Book Q-Playing Football R-Reading Book
BP-Playing Football Q-Reading Book R-Dance Practice
CP-Playing Football Q-Reading Book R-Painting
DP-Doing Homework Q-Playing Football R-Reading Book


Ans 1:

DhritismanDas from Sfs, Guwahati
Class : Class 3

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(C):

  • Time duration for playing football = 30 minutes

           Time duration for reading book = 30 minutes
           So, activities that last for 1 hour in total are
           playing football and reading book.

  • The activity that lasted for 15 minutes only is painting.

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Abhinha Ajay Ovhal from Podar International School, Latur
Subject :IMO    Class : Class 1

Ans 1:

KARNIK NAYAL from THE MILLENNIUM SCHOOL, Noida
Class : Class 2
D

Ans 2:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 6

Ans 3:

Abhinha Ajay Ovhal from Podar International School, Latur
Class : Class 6

Ans 4:

KARNIK NAYAL from THE MILLENNIUM SCHOOL, Noida
Class : Class 2
D

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Vedant Sharma from Silver Oaks , Hyderabad
Subject :IMO    Class : Class 7

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