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Amit from psbb millenium school.omr, Chennai
Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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Dhairya Godbole from KLE Eng Medium School, SOLAPUR
Subject :IMO    Class : Class 3

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rachana from delhi public school, NACHARAM
Class : Class 3
mental burra

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Advika Narkar from VIBGYOR High Airoli, Navi Mumbai
Class : Class 5
Question, is wrong

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rachana from delhi public school, NACHARAM
Class : Class 3
endi ra antha tough questions isthanu niku pain theliadhura easy questons ivvu

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Sanjivani Saha from Chrysalis High, Bangalore
Class : Class 6
cool answers

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vineet8026@gmail.com from dps, Doha
Class : Class 1
English please

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Parth Bansal from DAV Gloval School , Patiala
Class : Class 5

Ans 7:

Sri Vaishnav Reddy from Tiny Tots Olympiad School, Narasaraopet
Class : Class 3
answer is C, observe circle to be completed

Ans 8:

rachana from delhi public school, NACHARAM
Class : Class 3
munda yedhava sachinoda sighuledha niku mental burra

Ans 9:

rachana from delhi public school, NACHARAM
Class : Class 3
cheeeeeeeeeeeeeeeeeeeeeeeeee

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Anirudh Jhunjhunwala from JBCN International School, Parel, Mumbai
Subject :IMO    Class : Class 7

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Anurag Lakhotia from ,
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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T. V. Narasimha Rao from ,
Subject :IMO    Class : Class 8

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Bindeshwari Prasad from ,
Class : Class 8
it would be 10. [n-2]180=1440 180n-360=1440 180n=1800 n=1800/180 = 10

Ans 2:

sanjay shete from ,
Class : Class 8
the answer should be 10 because= (n-2)*180=1440

Ans 3:

Admin from SOF, Noida
Class : Class 10
Answer: C

Solution
If a polygon has 'n' sides, then it is divided into (n – 2) triangles. The sum of the angles of a triangle = 180°. Therefore, the sum of interior angles of a polygon having n sides is (n – 2) x 180.
(n - 2) x180 = 1440
n - 2 = 1440/180 = 8
n = 8 + 2 = 10

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Rahul Jha from Delhi Public School BN, Bengaluru
Subject :IMO    Class : Class 6

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suhas from podar, kalyan, Dist thane
Subject :IMO    Class : Class 4

Ans 1:

Admin from SOF, Noida
Class : Class 10
Answer : D
Solution
Let number of peacocks be p
Let number of lions be l
Number of legs = 15
Number of heads = 15 + 25 = 40
p + l = 15
2p + 4l = 40
Solving the above equations
p = 10 , l = 5
So there are 5 more peacocks than lions.

Ans 2:

Vrushti from swami vivekanand english primary school, Mumbai
Class : Class 4
Heads ( Lions + Peacocks) = 15, No. of Legs = 25 +15 = 40. Since total legs were 40 no. of lions has to be less than 10 (because 10 x 4 legs = 40 which means zero peacock, which is not possible...) . so if we take 5 lions and 10 peacocks, total heads = 15 & total legs = 5 x 4 + 10 x 2 = 40 legs. Thus the answer is 5 peacocks were more than lions.

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Aniket Srivastava from Victorious Kids Educare, Pune
Subject :IMO    Class : Class 5

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Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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suhas from podar, kalyan, Dist thane
Subject :IMO    Class : Class 4

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Kushal from Chirec, Hyderabad
Class : Class 7
the answer is 19803 because you should find the difference between 14365-(5876-3243)=11732 23512-(7584-3875)=19803

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Soham De from DPS, Nerul, Mumbai
Class : Class 5
19803

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mamta from army public school, ramgarh
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

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