# User Forum

Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 4
x = 4, y =6, z = 8, M = 1 therefore answer is 6

Class : Class 4
Ans-D

## Ans 3:

Class : Class 4
X = 4,y=6,z=8 and m=1 . Therefore the answer is B (6)

Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 6
it is d only

Subject :IMO    Class : Class 3

Class : Class 5

## Ans 2:

Class : Class 5
Answer is C because that is THE BEST for this situation. If we use Kilograms, the weight will come in fractions and hence is not THE BEST answer.

## Ans 3:

Class : Class 4

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 5
Answer is D Reason: Maya today is 18 years. So six years back she was 12 years old. At that time Namita was 48 (4 times Myaya's age), So Namita is 54 years ow (after 6 years). So Namita + Maya is 54 + 18 = 72

## Ans 2:

Class : Class 3

Subject :IMO    Class : Class 4

Class : Class 1

Subject :IMO    Class : Class 8

Class : Class 1

Subject :IMO    Class : Class 3

## Ans 1:

Class : Class 5
We have to multiply 6 and 5 then 3 and 2 then add the both products

## Ans 2:

Class : Class 5
Answer is A.Multiply 6 and 5 then 2 and 3 then add both products

## Ans 3:

Class : Class 10

Solution
5x2 + 4x6 = 34
3x10 + 7x2 = 44
6x5 + 3x2 = 36

Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 8
3 times

Subject :IMO    Class : Class 5

Class : Class 6
no

Class : Class 6

Class : Class 6
12