International Maths Olympiad Forum By SOF Olympiad Trainer - Page 576
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Garv Agarwal from Somerville School Noida, Noida
Subject :IMO    Class : Class 6

Ans 1:

Kavitharini Joseph from HUS, Chennai
Class : Class 6
how?

Ans 2:

Sahil Tejam from NPS Indiranagar, Bengaluru
Class : Class 6

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Garv Agarwal from Somerville School Noida, Noida
Subject :IMO    Class : Class 6

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A Ramakrishna Rao from D A V Public School. Unit 8. Bhubaneswar , Bhubaneswar
Subject :IMO    Class : Class 6

Ans 1:

Dheer Pandey from Sentia The Global School, Hyderabad
Class : Class 10
its d 1\15

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Manvi Mundepi from Montfort School Roorkee, Roorkee
Subject :IMO    Class : Class 6

Ans 1:

Nivedhini from Vivekanada Vidyalaya Chitlapakkam, Chennai
Class : Class 9
INDIA invented zero and its inventor is Bramagupta or Aryabhatta

Ans 2:

Gauri Singh from St Johns School Marhauli, Varanasi
Class : Class 8
India invented 0 and its inventor is Aryabhatta.

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Manvi Mundepi from Montfort School Roorkee, Roorkee
Subject :IMO    Class : Class 6

Ans 1:

Aryan Mohapatra from DAV PUBLIC SCHOOL,UNIT-8, Bhubaneswar
Class : Class 8
The answer is A

Ans 2:

Aryan Mohapatra from DAV PUBLIC SCHOOL,UNIT-8, Bhubaneswar
Class : Class 8

Ans 3:

Shreyansh Gupta from MVN, faridabad
Class : Class 6
okk

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Rs from DPS, Delhi
Subject :IMO    Class : Class 4

Ans 1:

DAIWIK SAHA from DUDES N DOLLS, FARIDABAD
Class : Class 8
a is the correct answer

Ans 2:

Kaustubh M Sawale from Campion school, Bhopal
Class : Class 6
A is the right answer

Ans 3:

Rachel from Mount litera Zee School Goa, Goa
Class : Class 7
b is the correct answer

Ans 4:

Manasvi pandey from Dps haldwani, Haldwani
Class : Class 3
B is correct

Ans 5:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
I did A but then I understood that holidays end at 13 but he will join on 14

Ans 6:

Vania Aravindan from Unicent School , Miyapur Hyderabad
Class : Class 8
A is the right one

Ans 7:

Saipriya from Sankara, Chennai
Class : Class 9
ans is be b ma because holidays till 13th but he will join on 14th only

Ans 8:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
Class:

Ans 9:

Sameer Anand from ST MICHAEL'S HIGH SCHOOL, PATNA
Class : Class 8
A is the right answer

Ans 10:

Kaustubh M Sawale from Campion school, Bhopal
Class : Class 6
B is the right answer as the date he will join is 14th Oct

Ans 11:

IAMLOST from ABC, Pune
Class : Class 8
ans will be b because holidays till 13th but he will join on 14th

Ans 12:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4
no b

Ans 13:

Vedang Bhardwaj from Lotus Valley, Gurgaon
Class : Class 4

Ans 14:

Aaryaman Pradhan from De paul School , Berhampur
Class : Class 5
a is the correct answer

Ans 15:

Aviya Daniel from HIM ACADEMY PUBLIC SCHOOL, Hamirpur
Class : Class 4

Ans 16:

Manasvi pandey from Dps haldwani, Haldwani
Class : Class 3
B is the correct

Ans 17:

Ryan Majumdar from Epistemo , Hyderabad
Class : Class 4
A is the correct answer.

Ans 18:

Vania Aravindan from Unicent School , Miyapur Hyderabad
Class : Class 8

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Mehrin from DPS, Riyadh
Subject :IMO    Class : Class 2

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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

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Champ from Reliance Foundation School, Mumbai
Subject :IMO    Class : Class 7

Ans 1:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

Ans 2:

Varnit khurana from Saint kabir school, Hissar
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.

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Adnan Sathik from Birla Public School , CHENNAI
Subject :IMO    Class : Class 3

Ans 1:

Vivaan Pathak from Prudence School , Ashok Vihar, Delhi
Class : Class 4
B Question

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