Class : Class 9
answer should be 'A' as it is directly proportional and in directly proportion the formula is x1/y1 = x2/y2
Ans 2:
Class : Class 3
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Ans 9:
Class : Class 3
ANSWER should be D definitely.There are only 10 sleeping lines not 11 and there are 6 circles so 6 curved lines.
Ans 12:
Ans 13:
Class : Class 3
the answer is definitely D i cant see more than 10 sleeping lines. i hope such error doesnt take place while checking the papers.
Ans 14:
Class : Class 3
There are 6 circles, so there are 6 curved lines but there are only 10 sleeping lines. Hence correct answer is d
Ans 17:
Ans 26:
Class : Class 5
All of you are sleeping?You are sleeping in day and not in night? Correct answer is D because there are not more than 10 sleeping lines.There are 6 curved lines. All of you should rest at night and sleep and relax. Next day you open this option 34 in mock test 2,you see that there was 6 curved lines and 10 sleeping lines and you think that 'I was mistake to see that 1curved line and 11 sleeping'.Hence the correct answer is option D.Not A.
Ans 36:
Class : Class 4
Yes. Answer is D. There are 10 sleeping lines not 11. Proper explanation should be provided as to how counting of lines is done.
Ans 37:
Class : Class 5
there is no clarity. they are diamonds not circles as per the answer .is this eye test or math test as after zooming also not clearly visible
Ans 39:
Class : Class 5
And you cannot see use spectacle to see sharp .You cannot see with spectacle use the spectacle at -1.
Ans 41:
Class : Class 5
The ans for this question is option BJishnavi Patnaik from Mount Litera Zee scool,UdaipurGrade 3
Ans 44:
Class : Class 4
it’s definitely option D not A because there are not more than 10 sleeping lines and there are six circles in picture
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Match the following.
| Column I | Column II |
| (i) The additive inverse of 2 |
(A) 0 |
| (ii) The greatest negative integer |
(B) - 2 |
| (iii) The smallest integer greater than every negative integer |
(C) 2 |
| (iv) Sum of predecessor and successor of 1 |
(D) - 1 |
A (i)→(C), (ii)→(D), (iii)→(A), (iv)→(B)
B (i)→(B), (ii)→(D), (iii)→(A), (iv)→(C)
C (i)→(C), (ii)→(D), (iii)→(B), (iv)→(A)
D (i)→(B), (ii)→(C), (iii)→(A), (iv)→(D)
Ans 2:
Class : Class 7
answer is B. it is actually a bit trcky as A and B are in same colour So, we need to focus a bit
Ans 3:
Class : Class 6
The problem is that A and B Are both in orange.. Is it just me or is it for everyone?
Ans 7:
Class : Class 6
Kushal fool ...can't solve this easy sum properly😆😆😆😆!!!
Ans 8:
Class : Class 6
IT IS A. GREATEST NEGATIVE INTEGER IS 1, 0 2=2 PREDECESSOR SUCCESOR OF 1 , ADDITIVE INVERSE OF 2 IS -2 AND SMALLEST NUMBER GREATER THAN EVERY NEGATIVE INTEGER IS 0