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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 9
Arithmetic progression (AP) is a type of series where there is a common difference between the subsequent numbers in the series.

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Subject :IMO    Class : Class 2

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Class : Class 10
3,27,765.35433070866141732283464567

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Subject :IMO    Class : Class 1

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 9
Hi there!!! I think the reason for your question would be that the NCO 2016 dates are much closer than IMO. You know mock tests helps in improving the topic. Well keep expectations for an IMO mock test because I want one for NSO. Thank you!

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Class : Class 9
Maharajganj

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Class : Class 9
Mock tests are available only a week before the exam

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 2

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Class : Class 4
blue whale

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
A fraction whose deno minator is a whole number,other than 10,100,1000, etc., is called a vulgular fraction. Ex. 2/9, 4/13 ,etc.,are vulgular fraction

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Class : Class 7
Vulgar fractions are fractions with denominator not 10,100,1000 and etc. Ex:45/56,89/90 etc

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Class : Class 9
The fraction whose denominator is a whole number other than 10,100,1000 is called vulgar fraction. for ex 5/7,8/6,6/8.

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Subject :IMO    Class : Class 8

Ans 1:

Class : Class 8
281.6

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Class : Class 8
281.6

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Class : Class 8
281.6

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
yeah the answer is 1000 trees. bro because see 4km 800m = 4800 by multiply we had converted it to metres to solve the sum. then step2= we will divide it to 9.6 because it has said to have intervals and to find the intervals we need to divide as we dont know how is the length is by after the interval and after the answer will be 500 step3= then the trees are planted both sides of the roads so multiply with or by 2 and the answer is 1000 trees.

Ans 2:

Class : Class 7
1000 trees

Ans 3:

Class : Class 6
HOHOUFYDVJ,VJG

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7
(H)2=(P)2+(B) 2

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Class : Class 7
A2+B2=C2

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Class : Class 7
(H)2=(P)2+(B) 2

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Class : Class 9
(H)2=(P)2+(B)2

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Class : Class 8
Hypotenuse=(side1)*2+(side2)*2

Ans 6:

Class : Class 7
Hypotenuse=base×base+hieght×height Base=hypotenuse×hypotenuse -height ×height Height=base×base - hypotenuse×hypotenuse

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Class : Class 8
square of base + square of perpendicular side = square of hypoteneuse

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Class : Class 7
Square of hypotenuse=Square of its legs

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Class : Class 7
(H)2=(P)2+(B) 2

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Class : Class 8
Asquare+B square = C square (hypotenuse)

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Class : Class 8
a2+b2=c2

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Class : Class 10
Hypotenuse^2= P^2 + B^2 Here, P=perpendicular height and B=base.

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Class : Class 7
The pythagoras' theorem states that the square of the hypotenuse is equal to the sum of the square of the other 2 sides. The equation would be hyp2=S12+S22 note: the 2 is the power of two

Ans 14:

Class : Class 9
square of hypotenuse=sum of square of other 2 legs in a right angled triangle

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Class : Class 8
AB2+BC2=AC2 THIS MEANS THAT IN A TRIANGLE WHEN WE ADD THE SQUARE OF THE BASE AND PARALLEL ANGLE IT WILL ALWAYS BE EQUAL TO THE HYPOTENUSE.

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Class : Class 10
a = 1 side, b = another side, c = hypotenuse (the longest side). The formula is: a2 + b2 = c2 (the two means squared, not multiplied by two). The formula only works in right-angled triangles.

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