International Maths Olympiad Forum By SOF Olympiad Trainer
  1. Home
  2. Forum

User Forum

Ask Your Question
Bhumika from Navy children school, Mumbai
Subject :IMO    Class : Class 4

Post Your Answer

divya sree from The hyderabad public school , Hyderabad
Subject :IMO    Class : Class 7

Post Your Answer

divya sree from The hyderabad public school , Hyderabad
Subject :IMO    Class : Class 7

Ans 1:

A Malik from The Mothers International School, New Delhi
Class : Class 7
5/8=10/16=20/32...so option B is out (19/32 is less than 20/32) Option C is out (10/16 is is greater than 8/16) and for same reason option D is also out So answer is option A

Ans 2:

KRITHIGHA SHRI M P from KAMALA NIKETAN MONTESSORI SCHOOL, TRICHIRAPPALLI
Class : Class 7
the LCM of 8,16 and 32 is 32 5/8=20/32 8/16=16/32 21/32=21/32 therefore, 16/32<20/32>21/32 also, 8/16<5/8>21/32 therefore 5/8 is between 8/16 and 21/32

Post Your Answer

Bindiya Bhoi from null, null
Subject :IMO    Class : Class 5

Ans 1:

Bindiya Bhoi from null, null
Class : Class 4

Ans 2:

vatsala from DPS, Durg
Class : Class 5

Post Your Answer

Samyak Jain from CCA School, Gurugram
Subject :IMO    Class : Class 5

Ans 1:

Samyak Jain from CCA School, Gurugram
Class : Class 5
sorry a

Ans 2:

Samyak Jain from CCA School, Gurugram
Class : Class 5
but since it was after 11th that is why the answer was c

Ans 3:

Arav Aanand from Father Agnel School, Noida
Class : Class 6
What is the number between 11 and 13 = 12 So it is B Others are false: I request you all to check your question and your answer

Ans 4:

Samyak Jain from CCA School, Gurugram
Class : Class 5
it could be a or c to

Ans 5:

Samyak Jain from CCA School, Gurugram
Class : Class 5

Post Your Answer

Avantika Raj from Delhi Public School, Bengaluru
Subject :IMO    Class : Class 3

Ans 1:

Avantika Raj from Delhi Public School, Bengaluru
Class : Class 1
answer is b

Post Your Answer

Rishabh from Baala Balaga,
Subject :IMO    Class : Class 8

Given below are the steps of construction of a quadrilateral PQRS, where PQ = 5.5 cm, QR = 8.5 cm, ∠P = 75°,
∠Q = 105°, ∠R = 120°. Which of the following is a wrong step?
(i) Draw PQ = 5.5 cm.
(ii) Draw ∠XPQ = 75° at P and ∠PQY = 105° at Q.
(iii) With Q as centre and radius QR = 5.5 cm, draw an arc to intersect QY at R.
(iv) At R, draw ∠PSR = 120° such that RT meets PX at S.
PQRS is the required quadrilateral.

A(iii) only
B(ii) & (iv) only
C(iii) & (iv) only
D(iv) only


Confusing question. After step 3 is wrong, step 4 is wrong by definition

Post Your Answer

Avantika Raj from Delhi Public School, Bengaluru
Subject :IMO    Class : Class 3

Ans 1:

Avantika Raj from Delhi Public School, Bengaluru
Class : Class 1

Post Your Answer

Bindiya Bhoi from null, null
Subject :IMO    Class : Class 5

Post Your Answer

Ami Buch from DPS Gandhinagar, Gandhinagar
Subject :IMO    Class : Class 8

Ans 1:

Kushi V from Jss Public School, bangalore
Class : Class 8
C

Post Your Answer