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Anand Mahajan from ,
Subject :IMO    Class : Class 4

Ans 1:

Sunita from Dps, Greater Noida
Class : Class 9
Answer : b Solution Smallest : 4608 Largest : 4688 Numbers between smallest and largest : 4640, 4680 Sum = 4640 4680 = 9320 So B is the right answer

Ans 2:

Admin from SOF, Noida
Class : Class 10
Answer : b
Solution
Smallest : 4608
Largest : 4688
Numbers between smallest and largest : 4640, 4680
Sum = 4640+4680 = 9320
So B is the right answer

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Yash Mehta from GIIS, Singapore
Subject :IMO    Class : Class 4

Ans 1:

FIONA GOMES from LOTUS VALLEY GURGAON, Gurgaon
Class : Class 4
answer supposes to be C, why mentioned as A????

Ans 2:

Priya Ponmurugan from Gateway international school, chennai
Class : Class 4
The answer c only...

Ans 3:

Sarthak from St Anthony Senior Secondary School Hiran Magri Udaipur, Udaipur
Class : Class 8
I am agree with Angel Gomes..

Ans 4:

NIRMAY JOSEPH from St Columba's School, New Delhi , New Delhi
Class : Class 9
I also fèel so.

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Shramana Bhattacharya from BpDAV School, Hyderabad, Hyderabad
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
can i buy cialis over the counter http://canadian-pharmasy.com

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Nishtha Pahuja from DPS, Sector45, Gurgaon
Subject :IMO    Class : Class 7

Ans 1:

Hitesh Vora from Bunt Sangha's S M Shetty International School , Mumbai
Class : Class 5
how is answer arrived?

Ans 2:

Nisha Nair from City , Pune
Class : Class 7

Ans 3:

from , Kolkata
Class : Class 9

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Darshan Garg from Sri Chaitanya Techno School, Bengaluru
Subject :IMO    Class : Class 4

Ans 1:

Admin from SOF, Noida
Class : Class 10
Answer : A. 5265
There was a mistake in the options. It has been corrected now.

Solution
Biggest 4 digit number formed from these digits = 8743
Smallest 4 digit number formed from these digits = 3478
Difference = 8743 - 3478 = 5265

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RAJESH DEWANGAN from ,
Subject :IMO    Class : Class 4

Ans 1:

sai ramakrishna GUDIMETLA  from AMM MATRICULATION HIGHER SECONDARY SCHOOL, Chennai
Class : Class 5
Option A 84 m is the right answer. Solution : The area of square is 144 m as given. Hence, the side of square is 12 m. The length of one smaller square in the shaded square is 6 m. Hence the length of the rectangle is 6+6+6+6 =24 the breadth of rectangle is 6+6+6=18 The perimetre of rectangle is 2(l+b) = 2 (24+18) = 2*42 = 84 m

Ans 2:

Vrushti from swami vivekanand english primary school, Mumbai
Class : Class 4
Ans is 84. Area of the square = 12 x 12 = 144 which means 12 is the length of two sides of the square, therefore each side will be 6 and there are 14 sides. Hence the perimeter is 14 x 6 = 84

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Shradha82 from Euro school , Pune
Subject :IMO    Class : Class 4

Ans 1:

Anjala Ambade from ,
Class : Class 4
ans-d

Ans 2:

Reshmi Arora from Lotus valley noida, Noida
Class : Class 4
ooliooli

Ans 3:

Soham Gupta from JSSIS Dubai, Dubai
Class : Class 6

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Agrim Goyal from ,
Subject :IMO    Class : Class 6

Ans 1:

Rishit Sharma from Nehru World School, Ghaziabad
Class : Class 7
Their answer is wrong

Ans 2:

Khush Narwal from ,
Class : Class 6
C

Ans 3:

Admin from SOF, Noida
Class : Class 10
Answer : C We have corrected the answer. Thanks for pointing out the mistake.

Ans 4:

Devang Shukla from Ryan Christian School, Mumbai
Class : Class 9
The answer is C

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kaithabjeetsingh@gmail.com from the shri ram school aravali, Gurgaon
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

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kaithabjeetsingh@gmail.com from the shri ram school aravali, Gurgaon
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

Ans 2:

manushri from akis, hyd
Class : Class 9

Ans 3:

from , Manesar
Class : Class 7

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