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Subject :IMO    Class : Class 9

Following are the steps of construction of a ∆ABC in which AB = 5 cm, ∠A = 30º and AC – BC = 2.5 cm. Arrange them and select the CORRECT option.
(i) Draw ∠BAX = 30º
(ii) Draw the perpendicular bisector of BD which cuts AX at C.
(iii) Draw AB = 5 cm
(iv) Join BD
(v) Join BC to obtain the required triangle ABC
(vi) From ray AX, cut off line segment AD = ACBC = 2.5 cm

A(i) → (iii) → (iv) → (v) → (vi) → (ii)
B(iii) → (i) → (vi) → (iv) → (ii) → (v)
C(iii) → (i) → (ii) → (v) → (iv) → (vi)
D(iii) → (ii) → (iv) → (i) → (vi) → (v)


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Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 1

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Class : Class 5

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Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 3

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Subject :IMO    Class : Class 7

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Class : Class 7

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Subject :IMO    Class : Class 9

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Class : Class 9
Solve- In 1st figure, 6^3+4^3+3^3+2^3=315 ​ In 2nd figure, 11^3+8^3+7^3+6^3=2402 Similarly, in 3rd figure, 5^3+4^3+1^3+x^3=1190 = 190+x^3=1190 = x^3=1000 = x=10 So, correct answer is D) 10

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Class : Class 10
how

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Subject :IMO    Class : Class 4

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Class : Class 4
please tell

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Class : Class 4

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Subject :IMO    Class : Class 4

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Class : Class 4

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