International Maths Olympiad Forum By SOF Olympiad Trainer

# User Forum Subject :IMO    Class : Class 4

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Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 4
Answer is D). How? So let’s hear the question and answers fill in the blanks. • There were 40 children at a party. 14 of them were boys. __P__ fraction of children were girls. • Cost of a teddy bear is of the cost of a doll. If cost of the teddy bear is ₹ 114, then cost of the doll is ₹ __Q__ . • Difference between is __R__. • If then x = __S__. P Q R S A 7/20 76 5/8 1/4 B 13/20 76 7/8 1/4 C 7/20 171 5/8 3/4 D 13/20. 171 7/8 3/4 So the first question is. • There were 40 children at a party. 14 of them were boys. __P__ fraction of children were girls. So the answer is 26/40 or 13/20 because if there are 14 boys out of 40 children then 26 girls out of 40 children answer for the first question is 26/40 or 13/20. So option A) and C) cannot be the answer because they are not equivalent to 26/40 or 13/20. Now let’s hear the second question. • Cost of a teddy bear is of the cost of a doll. If cost of the teddy bear is ₹ 114, then cost of the doll is ₹ __Q__ . So the cost of the doll is ₹171 because cost of a teddy bear is 2/3 cost of a doll And the cost of the teddy bear is also equal to ₹114 so how get answer as ₹171 you have to divide ₹114 by 2 to get 1/3 of cost of the doll and then we ₹57, and then we multiply ₹57 by 3 to get the cost of the doll answer is ₹57 + ₹57 + ₹57 = ₹114 + ₹57 or ₹171. Now the option B) cannot be the answer because it is not equivalent to ₹171. Now you’ll are thinking that why I didn’t show the explanation of questions 3 and 4. I did not show you questions 3 and 4 because there are only 4 options and in answers none of the options none of these as their answers. Hence we have an answer which is D).

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Subject :IMO    Class : Class 4

## Ans 1:

Class : Class 4
According to BODMAS or DMAS, first / (divide),then * (multiply), then (add) and then - (subtract). So answer should be: S * R - P Q= 5 x 7 - 2 8= 35 - 2 8= 35 - 10= 25

## Ans 2:

Class : Class 4
Hope you answer soon

## Ans 3:

Class : Class 4
Is there any rule for DMAS solving? Hope you answer both my questions. 1. According to......... and 2. Is there any ......................

Class : Class 3

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Subject :IMO    Class : Class 8

Class : Class 8

## Ans 2:

Class : Class 9
Let the sum be x. Compound interest: P(1+r/100)^n-P =x(11/10)^2-x Taking x common, x[(121/100)-1] =21x/100 Simple interest:p*r*t/100 =x*10*2/100 =x/5 Compound interest - simple interest =500 21x/100-x/5=500 x/100=500 x=50000

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Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 7
414720 /144 = 2880 correct answer is D

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 6

## Ans 1: (Master Answer)

Class : Class 1

(A): Let the  other number be y.
HCF × LCM = Product of numbers
11 × 7700 = 275 × y
y = 308

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Subject :IMO    Class : Class 7

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Subject :IMO    Class : Class 3

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Subject :IMO    Class : Class 6

## Ans 1: (Master Answer)

Class : Class 1

(C): Two plots have same perimeter:
So, 60 × 3 = 2 × ( length + 30)
90 = length + 30
Length = 60 m
Hence, area = 60 × 30 = 1800 sq. m