International Maths Olympiad Forum By SOF Olympiad Trainer - Page 807

User Forum

Subject :IMO    Class : Class 2

Post Your Answer

Subject :IMO    Class : Class 3

Ans 1:

Class : Class 8
the answer is random access memory

Ans 2:

Class : Class 8
the answer is random access memory

Post Your Answer

Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3
denominator is a number in the bottom of a fraction .It is the whole number for which that fraction is written e.g 3/4 the denominator will be 4 because the whole thing is divided into 4 pieces and numarator 3 represents 3 parts.

Ans 2:

Class : Class 6
A Denominator is a number found at the bottom of a fraction. It is the whole number for which that fraction is written.

Ans 3:

Class : Class 3
(Denominator)the number below the fractional bar

Post Your Answer

Subject :IMO    Class : Class 3

Ans 1:

Class : Class 5
numerator is upper part of a fractional number exa-2/3,here 2 is the numerator.

Post Your Answer

Subject :IMO    Class : Class 8

Ans 1:

Class : Class 8
I guess that you meant Componendo et Dividendo. This is a very useful property of proportion that states: If a/b=c/d, then, (a+b)/(a-b)=(c+d)/(c-d)

Post Your Answer

Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5
1/2 x Height x Base

Ans 2:

Class : Class 8
1/2 x height x base

Ans 3:

Class : Class 10
height x base divided by 2

Post Your Answer

Subject :IMO    Class : Class 10

Ans 1:

Class : Class 10
my friend, i think that this will happen like this let us assume that _ =m log 5 =2 m so m ^2=5 so m=sqrt(5)

Ans 2:

Class : Class 10
5^1/2

Post Your Answer

Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
1+2+3-2=2+_ Ans. 2

Ans 2:

Class : Class 8
The answer is 2

Ans 3:

Class : Class 3
2

Ans 4:

Class : Class 7
The answer is 2. It is because 1+2+3-2=4. It is also equal to 2+2. 2+2 is also equal to 4.

Ans 5:

Class : Class 10
2

Ans 6:

Class : Class 8
2

Ans 7:

Class : Class 9
the answer is 2

Ans 8:

Class : Class 6
the answer is 2 .

Ans 9:

Class : Class 8
1+2+3-2=2+2 SO 2 WILL BE THE ANSWER

Ans 10:

Class : Class 9
answer is 2

Post Your Answer

Subject :IMO    Class : Class 3

Ans 1:

Class : Class 6
the correct answer is 792

Ans 2:

Class : Class 3
790

Post Your Answer

Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3
Given: 1) Pens brought = 458 pens. 2) Pens lost = 78 pens. 3) Pens brought again = 47 pens. Solution: Mr. Joan brought 458 pens but lost 78 of them, Therefore, He has 458 - 78 = 380 pens. But, He again goes to shop and bought 47 pens. So, He has 380+47 = 427 pens. Ans. Mr. Joan has 427 pens.

Post Your Answer