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Sehaj from Spring Dale Senior School, Amritsar
Subject :IMO    Class : Class 10

Ans 1:

Kapil Kumar from APS ALLD, Allahabad
Class : Class 10
Answer is (A) a=sin(A) + cos(A)........................................given as equation (1) a^2=sin^2(A) + cos^2 (A) + 2 sin(A)cos(A) a^2=1 + 2 sin(A)cos(A) therefore, sin(A)cos(A) = (a^2 - 1)/2..............................equation (2) b = {sin(A) + cos(A)} / sin(A)cos(A) b = a/a^2-1 x 2/1.............................................from equation (1) and (2) therefore b = 2a/a^2-1

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Sehaj from Spring Dale Senior School, Amritsar
Subject :IMO    Class : Class 10

Ans 1:

Riya from Nirmal vidyalaya, Jagdalpur
Class : Class 10
Ans is 6cm bcoz when we apply tangent secant theorem the wil get 6..cheers❤

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Rajendra Singvi from SHGS, Nandurbar
Subject :IMO    Class : Class 7

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SWAPAN KUMAR SAHA from ,
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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SWAPAN KUMAR SAHA from ,
Subject :IMO    Class : Class 7

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SWAPAN KUMAR SAHA from ,
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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SWAPAN KUMAR SAHA from ,
Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

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SWAPAN KUMAR SAHA from ,
Subject :IMO    Class : Class 7

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abhimanyu from KVA, Raipur, Raipur
Class : Class 7
4

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SWAPAN KUMAR SAHA from ,
Subject :IMO    Class : Class 7

Ans 1:

Rameshwari from Jain English School Ambad, Ambad
Class : Class 7
It's 1.4 feet.

Ans 2:

Dhruvan G from Indian School Al Ghubra, Muscat
Class : Class 8
Its four feet option(A)

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mitali from sandipani school nagpur , Nagpur
Subject :IMO    Class : Class 4

Ans 1:

Sharvi Deshmukh from BRPS, Pune
Class : Class 1
45

Ans 2:

ANIKET RAY from DPS ROURKELA, Rourkela
Class : Class 5
45 YEARS OLDER

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