International Maths Olympiad Forum By SOF Olympiad Trainer

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Subject :IMO    Class : Class 7

## Ans 1: (Master Answer)

Class : Class 1

Kindly repost the correct question

Subject :IMO    Class : Class 9

## Ans 1: (Master Answer)

Class : Class 1

The correct answer is A.

Given a right angled ΔABC,
where AB = AC and CD is the bisector of ∠C  Subject :IMO    Class : Class 3

## Ans 1: (Master Answer)

Class : Class 1

The correct answer is D.

Subject :IMO    Class : Class 5

## Ans 1: (Master Answer)

Class : Class 1

In mathematics, 'e' is a constant that is the base of the natural logarithm. It is the unique number whose natural logarithm is equal to one and its value is approximately 2.71828.

Subject :IMO    Class : Class 3

## Ans 1: (Master Answer)

Class : Class 1

The correct answer is C.

Handshakes by the first child = 6 (with remaining 6 children)

Handshakes by the second child = 5 (as the handshake with the first child is already counted)

Then, handshakes by the third child = 4 (as the handshakes with the first and second child are already counted)

Similarly, handshakes by the fourth, fifth and sixth child are 3, 2 and 1 respectively.

Since, the last child's handshakes are already counted, he/she will not make any new handshakes.

Therefore, a total of (6 +5 +4 + 3 + 2 + 1) = 21 handshakes took place.

## Ans 2:

Class : Class 3

Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 7
then the question turns to 2x(5x20x15) =30000, hence B is the correct answer

Class : Class 7

## Ans 3:

Class : Class 8
2X(5X20X15) =3000, so B is the answer

## Ans 4:

Class : Class 7
The answer is option B but you have typed 30000 but the answer is written is 3000

Subject :IMO    Class : Class 5

## Ans 1:

Class : Class 5
Please I want to tell something the spelling is wrong of genius

Subject :IMO    Class : Class 5

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Subject :IMO    Class : Class 2

## Ans 1: (Master Answer)

Class : Class 1

Here the correct answer is C.

No. of legs in 1 spider = 8

No. of legs Lakshay will see =  8 (No. of legs in 1 spider)  X  3 (No. of spiders) = 24