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Abin Jose from Delhi Public School, Sagar
Subject :IMO    Class : Class 8

Ans 1:

Shreyam Tripathy from Ann Mary School, Dehradun
Class : Class 10
third option is correct since in a kite, diagonals intersect at right angles and kite is not a rhombus. it does not talk about bisecting.

Ans 2:

from , Kalyan
Class : Class 9
2nd option

Ans 3:

Abin Jose from Delhi Public School, Sagar
Class : Class 3
Raunak Pandey yr answer is wrong , diagonals of a rectangle are not perpendicular

Ans 4:

Prachi from Holy Child Public school, Faridabad
Class : Class 10

Ans 5:

Abin Jose from Delhi Public School, Sagar
Class : Class 3
I feel all options are wrong

Ans 6:

Bhagyesh Kamal from DPS, Mumbai
Class : Class 8
c

Ans 7:

rajib jana from DPS MEGA City, Kolkata
Class : Class 8
@abin jose i agree

Ans 8:

Abin Jose from Delhi Public School, Sagar
Class : Class 3
First option is wrong because a parallelogram is not always necessary to be a square or a rectangle ,as they only have diagonals equal. Second option is wrong because rectangle does not follow this property which can be checked by using SAS congruence criteria. Third option is wrong because if the diagonals of a quadrilateral intersect at right angles then it is necessarily a rhombus, if u are thinking that square also have this property then add up a point that every square is a rhombus. Fourth option is wrong because every quadrilateral is not necessarily be a trapezium, a parallelogram or a kite as concave quadrilaterals are none of them.

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Shweta Garg from Vibgyor high, Vadodara
Subject :IMO    Class : Class 3

Ans 1:

Shiven Dinkar from DPS NOIDA Sector 30, Delhi
Class : Class 4

Ans 2:

Shweta Garg from Vibgyor high, Vadodara
Class : Class 8
THERE COULD BE MORE THAN 10

Ans 3:

Animesh Mishra from DPS NORTH BANGALORE, BENGALURU
Class : Class 3
There are 6

Ans 4:

BHAVYAA NAYYAR from CARMEL CONVENT SCHOOL, NEW DELHI
Class : Class 3
6

Ans 5:

Animesh Mishra from DPS NORTH BANGALORE, BENGALURU
Class : Class 3
There are 6

Ans 6:

Shiven Dinkar from DPS NOIDA Sector 30, Delhi
Class : Class 4
I know the answer is C but explain the solution

Ans 7:

Pranav M from PSBB, Chennai
Class : Class 10
Please mind the arrows. Find ways only that follows the arrows. So Ans will be 5

Ans 8:

Saanvi Sharma from Harvest International , Bangalore
Class : Class 5
If I follow the arrows I get 5

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bhavya garg from la bloosom school , jalandhar
Subject :IMO    Class : Class 6
ggg

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om nandanwar from springdel school , bhandara
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
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Ans 2:

Edhita Srivastav from New Horizon Gurukul, Bangalore
Class : Class 5
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Ans 3:

Sashrika Pasunoori from KV Gachibowli, Hyderabad
Class : Class 5
The master answer didn't solve my problem. Plss can somebody tell me the explanation and the answer?

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nimay gupta from Shiv Nadar School, noida
Subject :IMO    Class : Class 6

Ans 1:

Aadvik saini from Mvn sector 17, Faridabad
Class : Class 8
answer is c

Ans 2:

nimay gupta from Shiv Nadar School, noida
Class : Class 8

Ans 3:

Preeti tanwar from DON BOSCO ACADEMY, Patna
Class : Class 9
the answer is B

Ans 4:

Sharanyaa Tripathi from Uttam school for girls, Ghaziabad
Class : Class 8
Answer is C!!!

Ans 5:

Shreyansh Gupta from MVN, faridabad
Class : Class 7
bro the answer is legit c

Ans 6:

Adhrit from CHSV, Chennai
Class : Class 8
The answer is C

Ans 7:

R K Madhav from Kendriya Vidhyalaya Kottayam, Kottayam
Class : Class 7
What that is not the answer , answer is D

Ans 8:

R K Madhav from Kendriya Vidhyalaya Kottayam, Kottayam
Class : Class 7
What that is not the answer , answer is D

Ans 9:

Pisal Dhruv from Veer Bhagat Singh International School, Mumbai
Class : Class 7
c is the answer because 1 mother 3 unmarried daughters 2 sons have 4 daughters in total and two sons have two daughters in total and we also have to count the wives of the four sons. so altogether the female members are 14

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Utkarsh Chakravarty from Pinnacle High International School, Mumbai
Subject :IMO    Class : Class 5

Ans 1:

Arshi Jain from DPS noida, New Delhi
Class : Class 5
please correct your fake sign

Ans 2:

Mannat Verma from Vivek High School , Chandigarh
Class : Class 6

Ans 3:

JOIS GEORGE from Dimension, Singapore
Class : Class 5
Aren't all options wrong I'm still confused...

Ans 4:

Saloni Saini from JPHS, Jaipur
Class : Class 6
all options are wrong

Ans 5:

Aayansh sahu from Apeejay School, Ulwe
Class : Class 4

Ans 6:

Krethick Ravichandran from FIITJEE GLOBAL SCHOOL , India
Class : Class 9

Ans 7: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is C

(1.25 X 4) + (4.25 ÷ 5) = a X 1/4                                 

=> 5 + 0.85 = a X 1/4

=> 4 x 5.85 = a

=> 23.4 = a

 


Ans 8:

Krethick Ravichandran from FIITJEE GLOBAL SCHOOL , India
Class : Class 9

Ans 9:

Malavya Chaturvedi from Study Hall, Lucknow
Class : Class 8
in the question your division sign is looking like sign and I also zoomed it 20 times

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KANU TRIPATHI from Vibgyor High, Malad (East), Mumbai-400063, MUMBAI
Subject :IMO    Class : Class 9

Ans 1:

Madhu K from G.B.public school, melmaruvathur
Class : Class 9
The statement is true but there are only 6 postulate which does not include this There are infinite points on a line

Ans 2:

Arjun Phaneesh from Vidya Vardhaka Sangha Gandhi Centenary School, Bengaluru
Class : Class 10
Ya it's A they've given wrong

Ans 3:

Sujal Shishodia from HAPPY SENIOR SECONDARY SCHOOL, Jind
Class : Class 10
c

Ans 4:

from d.g.v. sr. sec. school, rohtak
Class : Class 9
correct is b

Ans 5:

Rudra kumar from Jawahar Navodaya vidyalaya, Sherghati
Class : Class 9
The correct option is c

Ans 6:

from , Bhubaneswar
Class : Class 9
A

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from ,
Subject :IMO    Class : Class 5

Ans 1:

Amlan choudhury from GD Birla center for education , Kolkata
Class : Class 7

Ans 2:

RAM CHARAN from Kennedy global, Hyderabad
Class : Class 5
A

Ans 3:

RAM CHARAN from Kennedy global, Hyderabad
Class : Class 5
11

Ans 4:

Shweta Garg from Vibgyor high, Vadodara
Class : Class 8
How did your answer came 11

Ans 5:

Aarav Hitesh Parikh from Gopal Sharma International School, Mumbai
Class : Class 8

Ans 6:

TANVI DAS from GAIL DAV Public School , Dibiyapur
Class : Class 8
Answer is A. Please see solution. Here, we have to add the upper two numbers and then divide it by the bottom number, then we get answer 7 in every case.

Ans 7:

Krethick Ravichandran from FIITJEE GLOBAL SCHOOL , India
Class : Class 9
how option A

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from ,
Subject :IMO    Class : Class 5

Ans 1:

Shweta Garg from Vibgyor high, Vadodara
Class : Class 8
sum of all numbers in a line is 15 6 4 5=15, 6 3 6=15, 6 8 1=15,7 5 3=15 so Answer is A

Ans 2:

Kuldeep Saxena from Podar Internation School ICSC Kalyan, Thane
Class : Class 5

Ans 3:

Aayansh sahu from Apeejay School, Ulwe
Class : Class 4
SUM OF ALL CHAIN IS 15 @ ANSWER A YAY MINE IS RIGHT.

Ans 4:

Pragnay Priyadarshi from Quantum Leap School, HYDERABAD
Class : Class 7

Ans 5:

Harsh Kumar from Maharishi Vidya Mandir, Guwahati
Class : Class 8
Sum of number in each chain is 15.

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giridhar bhat from Jindal Vidya Mandir, Toranagallu
Subject :IMO    Class : Class 1

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