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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 4
Shouldnt it be 15? The equation is (X 2) X [(9/5)X] = 59

Ans 2:

Class : Class 3
how did you get the answer

Ans 3:

Class : Class 6
how will we solve this?

Ans 4:

Class : Class 8
how will i solve this problem?

Class : Class 6
Got it

Class : Class 5

Ans 7:

Class : Class 3
Let Janak points = J | Adil A = J + 2 | Rohit R = (9/5) * J | Adil + Janak + Rohit = 59 | A + J + R = 59 | Replace as above | (J + 2) + J + (9/5)*J = 59 | 2J + 2 + 9J/5 = 59 | To remove 5 in denominator, multiply entire equation by 5 | 10J + 10 + 9J = 295 | 19J = 295 - 10 | 19J = 285 | J = 15 | Hence Janak's points = 15 | => Adil = J + 2 = 17 points |

Ans 8:

Class : Class 5

Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3

Subject :IMO    Class : Class 3

Class : Class 3

Class : Class 6
B

Ans 3:

Class : Class 5
The way I taught my child was to try with each option, that is, start with option A, assume 40 is the number of soldiers, then calculate no of legs of soldiers, then minus that from total no. of legs, and see if the resulting number gives u the required number of horses you need in order to get a total of 45 horses and soldiers. Repeat the same for option B, C and D. Answer is B. This is how we did it: Assume 35 as no. of soldiers 35x2 = 70 legs of soldiersM Minus 70 from 110 (total legs)= 40 legs 40 horses legs = 40 divided by 4 =10 horses Therefore 35 soldiers and 10 horses = 45 soldiers and horses totally

Ans 4:

Class : Class 4
The level of the question is certainly not for Class 3. It involves use of simultaneous equations. Answer is 35 soldiers.

Class : Class 3

Ans 6:

Class : Class 6
The answers in options needs to be considered while answering the question. The total number of horses and soldier in the troop is 45. Let us consider option A with 40 soldiers = 80 human legs so the balance legs are 30 which is not possible for horses as they have 4 legs. Going by option B= 35 soldiers = 70 human legs. So the balance legs remains 40, which is possible for 10 horses. Now the total number of horses and soldiers are 45 so 35 soldiers+10 horses = 45 and hence is a right answer. The balance options can be checked in similar way and will be found incorrect.

Ans 7:

Class : Class 3
it is not a class 3 question understand that

Ans 8:

Class : Class 3
Hey you don't understand

Subject :IMO    Class : Class 3

Ans 1:

Class : Class 3
Answer is D as per question

Ans 2:

Class : Class 8
in the question each is missing.. the balls are for each box

Class : Class 5

Ans 4:

Class : Class 2
solution is (24*5) (48*4)=312hence answer is B

Class : Class 8
D

Class : Class 3
D

Ans 7:

Class : Class 9
B312

Subject :IMO    Class : Class 5

Class : Class 1

Subject :IMO    Class : Class 5

Class : Class 1

Ans 2:

Class : Class 5

Subject :IMO    Class : Class 5

Ans 1:

Class : Class 9
option D 31 since it is a prime number

Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
A- EMI 1970 per month 3 years = 36 months Total Amount Paid in three years 36 x 1970 = 70920 B - Rajat Paid Advance - 35000 Total Amount Paid A +B 70920+35000= 105920 Answer is C

Class : Class 4

Ans 3:

Class : Class 4
3years=36 monthsEMIper month=1970EMI in three year=72920Rajat paid in advance=35000Total amount paid=70920 35000=105920......[C] is the answer............................

Class : Class 4

Ans 5:

Class : Class 8
3 years = 36 months, and EMI paid each month= 1970/-, so the total amount paid in EMI is 36 x 1970, which is 70920. Therefore, total value of the car is 35000 + 70920 = 105920/-.

Ans 6:

Class : Class 7
C

Subject :IMO    Class : Class 6

Ans 1:

Class : Class 7
C is the answer of this question

Class : Class 7
good question

Ans 3:

Class : Class 8
I THINK C. IS NOT THE NET OF THE SOLID

Subject :IMO    Class : Class 6

Class : Class 8
-25+10+0=-15