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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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Kabir Bajaj from P G Garodia School ICSE, Mumbai
Subject :IMO    Class : Class 3

Ans 1:

saina from dps, INDIRAPURAM
Class : Class 2

Ans 2:

Darshini Chakravarty from Pinnacle High International School, Mumbai
Class : Class 4

Ans 3: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

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Omayr from Army Public School Yol Cantt, Dharamshala
Subject :IMO    Class : Class 8

Ans 1:

Rgdn from SDIS, Gandhinagar
Class : Class 8
Answer is C. a^2 ÷ 2 Because diagonals of a square are equal. And area of rhombus formula can be used here because both have all sides equal. Area of rhombus= 1/2(diagonal 1 × diagonal 2) Because diagonals are equal, we write it as : a × a÷ 2 =a^2 ÷2

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Shantanu P Yadav from ST. Vincent Pallotti Nagpur, Nagpur
Subject :IMO    Class : Class 6

Ans 1:

Nisarg Milan Salot from Narayana E-Techno School, Mumbai
Class : Class 8
option B

Ans 2:

pranjal kaur from SVISG, DELHI
Class : Class 6
option B

Ans 3:

from ,
Class :
B: New number is smaller than original number.

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Aadithya John Gejo from Airforce school AV camp, Bangalore
Subject :IMO    Class : Class 4

Ans 1:

AREEN from BOLTON SCHOOL, Secunderabad
Class : Class 5
Answer is C as the question says 3098+1427<5420+2018 and we have to find how much less 3098+1427<5420+2018, which is 5420+2018-3098+1427 and to get this we have to follow the BODMAS rule, which is 7438-4525=2913.

Ans 2:

Dhanshree from Sunshine school, Karanja
Class : Class 4
The answer is C

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amol dewale from ,
Subject :IMO    Class : Class 7

Ans 1:

from DPS R.K. PURAM,
Class : Class 9
D

Ans 2:

Keshav from RPS , Mahendergarh
Class : Class 7
B

Ans 3:

Rishit Jain from Dps, Meeru5
Class : Class 10
Ans is d 20

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Achintya k j from KENDRIYA VIDYALAYA GOLE MARKET, NEW DELHI
Subject :IMO    Class : Class 7

Ans 1:

from , Kolkata
Class : Class 9
Angle BAC = x + 40 - x => 40 As triangle ABC is an isosceles triangle with AB = AC, angle acb = angle abc = x Therefore, as angle abc + angle acb + angle bac = 180 then, x + x + 40 = 180 =>2x = 180 - 40 =>2x = 140 =>x = 70

Ans 2:

from DPS R.K. PURAM,
Class : Class 9
d

Ans 3:

Keshav from RPS , Mahendergarh
Class : Class 7
D

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from , Kolkata
Subject :IMO    Class : Class 7

Ans 1:

Nilanjana De from Delhi Public School North, Bengaluru
Class : Class 8
Since triangle ABD is congruent to triangle ACD by SSS rule, so the altitude will also be the same. Which means BE=EC, as these are the altitudes of the triangles.

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Dhruv from Springdales, Dubai
Subject :IMO    Class : Class 4

Ans 1:

GAUTAM RAJESH from A E C S MANGNOLIA MAARUTHI , BANGALORE
Class : Class 4
The answer is b}4789

Ans 2:

dveep jain from mindful gurukul, Mumbai
Class : Class 4
Answer is B),how? Because the first line mentions that the forth digit is the greatest digit which is nine so option A) and option C) cannot be the answer. The second line mentions that the first digit is double of the number two so option D) cannot be the answer. So the answer is B)

Ans 3:

ikshika kumar from MVN SCHOOL, FARIDABAD
Class : Class 7
B) 4789

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