Subject :IMO Class : Class 6
Subject :IMO Class : Class 6
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 4
Ans 17:
Class : Class 4
I did A but then I understood that holidays end at 13 but he will join on 14
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Subject :IMO Class : Class 2
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Subject :IMO Class : Class 7
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Subject :IMO Class : Class 7
Ans 1:
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.
Ans 2:
Class : Class 7
As the length of side of square is 8 cm ,so it's area will be 8×8cm which is equal to 64 sq. cm.Now ,to find the area of triangle,i.e. the unshaded area ,we have to apply the formula of (1\2×base×height).Now the base is equal to the length of the side of square I.e. 8cm and the height is 3cm.Now the area of triangle is (1\2×8×3)cm =12cm.Now we have to subtract the unshaded area from the area of whole square I.e. 64 sq.cm-12 sq.cm =52sq.cm.So the answer is option B.
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Subject :IMO Class : Class 3