International Maths Olympiad Forum By SOF Olympiad Trainer - Page 588
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Riddhima Bhanja from presidium sector57, Gurgaon
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The angle OUT is of 180 degrees because it is a straight line. Hence, the angle RUN will be X+23=180-(32+23)=125.

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Riddhima Bhanja from presidium sector57, Gurgaon
Subject :IMO    Class : Class 5

Ans 1:

Aman from kv, Bengaluru
Class : Class 8
Answer is 192

Ans 2:

harsh joshi from podar international school, gwalior, Gwalior
Class : Class 5
The answer is 192 solution- 48/2=24 (24+24+24)+(24+24+24+24+24)=192

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SATISH GUDWANI from mvn, Faridabad
Subject :IMO    Class : Class 6

Ans 1:

Abhaid Goel from Indian School , Muladha
Class : Class 10
please explain it

Ans 2:

Agney Gurukul from ,
Class : Class 6
B

Ans 3:

Rcis from rcis, Bengaluru
Class : Class 9
the ans. is 200m . fig x has 12 sides so length of 1 side = 300/12 =25m . fig y has 8 sides so perimeter = 25 x 8 = 200m

Ans 4:

Harsh singh from Msm delhi cantt, new delhi
Class : Class 6
iu7tgo87rfo

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Suparn Agrawal from Delhi Public School Kashipur, kashipur
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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Kuldeep Battula from Deens Academy, Bengaluru
Subject :IMO    Class : Class 7

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varshith from Sri Sundaravalli Memorial School, Perungalathur
Subject :IMO    Class : Class 4

Ans 1:

aaryan chandrakant sonawane from nanded city public school, Pune
Class : Class 6
B is the answer means 140

Ans 2:

Shraddha from Delhi public school, Hyderabad
Class : Class 4
The answer is C only

Ans 3:

aaryan chandrakant sonawane from nanded city public school, Pune
Class : Class 6
B is the answer means 140

Ans 4:

varshith from Sri Sundaravalli Memorial School, Perungalathur
Class : Class 6
b=140 kg

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Rcis from rcis, Bengaluru
Subject :IMO    Class : Class 6

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Preety Sinha from DPS Gurgaon, Gurgaon
Subject :IMO    Class : Class 3

In the figure below, a large rectangle has a length of 60 meters and a width of 20 meters. A smaller rectangle has a length of 30 meters and width of 20 meters. Which statement is correct?



AThe perimeter of the large rectangle is twice the perimeter of the small rectangle.
BThe perimeter of the large rectangle is equal to the perimeter of the small rectangle.
CThe perimeter of the large rectangle is 30 meters more than the perimeter of the small rectangle.
DThe perimeter of the large rectangle is equal to 160 meters and the perimeter of the small rectangle is equal to 100 meters.

Ans 1:

Dhairya Godbole from KLE Eng Medium School, SOLAPUR
Class : Class 6
D is the right answer. Large Rectagle - 60+60+20+20 = 160 Small - 30+30+20+20 = 100

Ans 2:

Aryan Goyal from DPS , Dwarka, New Delhi
Class : Class 3
aaa

Ans 3:

Aditi Shiv Shankar Jaiswal from Delhi Public School Jeddah, Jeddah
Class : Class 4

Ans 4:

Darsh Vijay from The Orbis School, Pune
Class : Class 5

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Gaurav Modi from DELHI PUBLIC SCHOOL , RAIPUR, Raipur
Subject :IMO    Class : Class 9

Ans 1:

Esther Vajra from Dr. K.K.R. Gowtham School, Visakhapatnam
Class : Class 9
C

Ans 2:

Aryan S Kumar from Carmel School, Jorhat
Class : Class 9
Ans :C

Ans 3:

Ashish from DPS North, Bengaluru
Class : Class 9
answer is C

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Gaurav Modi from DELHI PUBLIC SCHOOL , RAIPUR, Raipur
Subject :IMO    Class : Class 9

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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