International Maths Olympiad Forum By SOF Olympiad Trainer - Page 329
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Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):

Number of chocolates Nimisha bought altogether = Number of chocolate boxes bought x Number of chocolates in each box
= 3 x 8 = 24


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Devang Shukla from Ryan Christian School, Mumbai
Subject :IMO    Class : Class 8

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ARADHYAA SHARMA from KULACHI HANS RAJ, delhi
Subject :IMO    Class : Class 1

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):


Total number of triangles = 12
Total number of squares = 4
So, there are (12 – 4) = 8 more triangles than squares.


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Naman Sharma from SB PATIL PUBLIC SCHOOL, Pune
Subject :IMO    Class : Class 9

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NYRAH GUPTA from Sat Paul Mittal School, Ludhiana
Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): (P) Total number of equal parts = 7
Number of shaded parts = 4
∴ Shaded fraction = 4/7
(Q) Total number of equal parts = 8
Number of shaded parts = 5
∴ Shaded fraction = 5/8
(R) Total number of equal parts = 11
Number of shaded parts = 5
∴ Shaded fraction = 5/11
(S) Total number of equal parts = 9
Number of shaded parts = 5
∴ Shaded fraction = 5/9
Thus, the ascending order of shaded
fraction is 5/11, 5/9, 4/7, 5/8, i.e., R, S, P, Q


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SIDDHARTH SOMANI from Vibgyor High, Mumbai
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):

Square is not present in the given figure.


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Tanav Jain from GCC International School, Thane
Subject :IMO    Class : Class 4

Ans 1:

Yatharth Banga from MVN school, Faridabad
Class : Class 7

Ans 2:

Shruti Agarwal from dpsnoida, Noida
Class : Class 4

Ans 3: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is option B. 


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madhu from sanskriti, new delhi
Subject :IMO    Class : Class 7

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Aneek Das from Sri ram narayan singh memorial High school, Kolkata
Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(C): Number of desktop computers = 100+150+200+300= 750

  Number of notebook computers = 50+75+150+200 = 475

Therefore, 750- 475 = 275 more desktop computers than notebook computers. 


Ans 2:

Mariya from Baden Powell Public school , Mysuru
Class : Class 6
Mariya from Baden Powell Public School, Mysoreclass : 6th 'a'(C): Number of desktop computers = 100 150 200 300=750 Number of notebook computers = 50 75 150 200 = 475 Therefore, now subtract 750 and 475, That is 750 -- 475 275So, 275 desktop computers are more than notebook computers .

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XXX from SVM, Bangalore
Subject :IMO    Class : Class 2

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is option D.


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