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B Murali Srinivas from ,
Subject :IMO    Class : Class 6

Ans 1:

JIVESH KUMAR from Cochin refineries school , Kochi
Class : Class 6
every natural number is a whole number

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Thamognya from nps, Singapore
Subject :IMO    Class : Class 5

Ans 1:

Ayush Kumar from Maria Assupta Sr. Sec. Convent School, KASHIPUR
Class : Class 5
The answer is option B.

Ans 2:

Gauri Singh from St. John's School, Marhauli, Varanasi
Class : Class 9
A. 0

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Shaurya Manjkhola from St Kabir Public School Chandigarh, Chandigarh
Subject :IMO    Class : Class 6

Ans 1:

Aditya Sai Vemparala from Amanora school, Pune
Class : Class 10

Ans 2:

JIVESH KUMAR from Cochin refineries school , Kochi
Class : Class 6
12 days

Ans 3:

Aditya Sai Vemparala from Amanora school, Pune
Class : Class 10
27

Ans 4:

Naumaan ahmed from Oyesters international, Pune
Class : Class 6
12 days

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Ojas Golyan from Indian school Sohar, Sohar
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is C.

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Ojas Golyan from Indian school Sohar, Sohar
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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Suraj Ramanan Gopal from BVM Global, bangalore
Subject :IMO    Class : Class 5

Ans 1:

Time to Learn from Hirananandani Foundation School, Thane,Mumbai
Class : Class 5
The answer is b as when we add 12 and 8 it is 20. Then, we multiply 12 by 8 it becomes 96. So 96- 76 is 20. Then let's add 13 and 9=22. Then multiply 13 by 9 the answer is 117. Subtract 117 by 95 =22. Then add 7 and 6 it makes 13. Then multiply 7 by 6 the answer is 42. Then 42 - 13 is 29. So the answer is 29.

Ans 2:

Aditya Sai Kedarisetty from Sri Kumarans childrens Academy DKS, Bangalore
Class : Class 6

Ans 3:

OISHIK KUNDU from Delhi Public school North kolkata, baranagar
Class : Class 4
The answer is b as when we add 12 and 8 it is 20. Then, we multiply 12 by 8 it becomes 96. So 96- 76 is 20. Then let's add 13 and 9=22. Then multiply 13 by 9 the answer is 117. Subtract 117 by 95 =22. Then add 7 and 6 it makes 13. Then multiply 7 by 6 the answer is 42. Then 42 - 13 is 29. So the answer is 29.

Ans 4:

Debarpan Das from Delhi Public School , Durgapur
Class : Class 6

Ans 5:

Vihaan Tyagi from Vikas the concept, Hyderabad
Class : Class 7
A and C are also correct

Ans 6:

OISHIK KUNDU from Delhi Public school North kolkata, baranagar
Class : Class 4
Let’s name the three set of numbers as Set P, Q and R. Now, first observe the numbers in Set P. If we multiply the top two numbers and then subtract the sum of them, we get the bottom number. (12 x 8) - (12 8) = 96 – 20 = 76. 76 is the bottom number. Let’s see if numbers in Set Q will also follow the same rule. (13 x 9) – (13 9) = 117 – 22 = 95. 95 is the bottom number. So, the rule is correct. That means the numbers in Set R will also follow the same rule. (7 x 6) – (7 6) = 42 – 13 = 29. 29 is the missing bottom number. Hence, the right answer is Option B.

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rbaiswar25@gmail.com from Somerville International School, Noida
Subject :IMO    Class : Class 2

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Prabhakar H.S. from ,
Subject :IMO    Class : Class 5

Ans 1:

Prabhakar H.S. from ,
Class : Class 1
IT IS SO HARD TO DO

Ans 2:

Prabhakar H.S. from ,
Class : Class 1

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monica jindal from British Co Ed high school, Patiala
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The rea of the square is 196 sq units. Hence, the side of the square will be the square root of 196 i.e 14 units Now, from the figure, we can see that each square cell is of 7 units Hence, the side EH is of 21 units and the side EF is of 28 units. Now, the perimeter will be 2(L+B) = 49 cm.

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monica jindal from British Co Ed high school, Patiala
Subject :IMO    Class : Class 5

Ans 1:

Dhruv from salwan junior school, New Delhi
Class : Class 5
b

Ans 2:

Harshita Seluca from Alpine Convent School , Haryana
Class : Class 5
Can anyone explain the question

Ans 3:

Shreyas Singh from Podar International School, Pune
Class : Class 6

Ans 4:

Devika PARAMBIKATTIL from Rustomjee Cambridge International School , Thane
Class : Class 6
As option bcd have triangular edges at the end, and option a do not have triangular edges option a is the answer

Ans 5:

Prapti Kumar from GD Birla Center For Education, Kolkata
Class : Class 8

Ans 6:

SJ HARITHA from PSBS, BENGALURU
Class : Class 7
HOW IS IT B DURAV

Ans 7:

Tamrashi Pani from National Public School, Bangalore
Class : Class 8
A is the correct answer ... I agree with devika

Ans 8:

Myshi bhandari from GMA, Dubai
Class : Class 5
But option b does not have a single angle greater than the right angle

Ans 9:

Nidhi Upadhyaya from S M shetty HIgh school, Mumbai
Class : Class 8

Ans 10:

Devesh Kumar Shrivastava from Ramjas School, Pusa Road, New Delhi
Class : Class 8

Ans 11:

Nishant Doshi from new era senior secondary school nizampura vadodara, Vadodara
Class : Class 7

Ans 12:

Debarpan Das from Delhi Public School , Durgapur
Class : Class 6

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