# User Forum Subject :IMO    Class : Class 6

Class : Class 1

Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 8

Subject :IMO    Class : Class 6

## Ans 1:

Class : Class 6
A

Subject :IMO    Class : Class 6

Class : Class 1

Subject :IMO    Class : Class 7

## Ans 1:

Class : Class 7
C . Can also be the answer.It is also not the net of cone

## Ans 2:

Class : Class 7
D is answer because it is not a net of the given figure

Subject :IMO    Class : Class 6

Subject :IMO    Class : Class 8

## Ans 1:

Class : Class 9
Quantity of mixture = 400 ml. Quantity of pure alcohol in it = 15 % of 400 = 15/100 * 400 = 60 ml Let's consider 'x ml' of pure alcohol was added to the mixture. After adding, Quantity of mixture = (400 + x) ml Quantity of pure alcohol in it = (60 + x) ml Strength = (60 + x)/(400 + x) = 32/100 => 100(60 + x) = 32(400 + x) => 6000 + 100x = 12800 + 32x => 100x - 32x = 12800 - 6000 => 68x = 6800 => x = 6800/68 => x = 100 Hence answer is 100 ml

## Ans 2:

Class : Class 8
Thanks

Subject :IMO    Class : Class 6

Class : Class 1

Subject :IMO    Class : Class 6

Class : Class 1

Class : Class 9