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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
sum of numbers from 1 to 90 = 90(90+1)/2 = 45 * 91 = 4095

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 7
15

Ans 2:

Class : Class 8
do the opposite calculations. 100/5=20 20+10=30 30/2=15

Ans 3:

Class : Class 8
fifteen/15

Ans 4:

Class : Class 8
15

Ans 5:

Class : Class 4
fifteen\15

Ans 6:

Class : Class 8
15

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 8
BODMAS is correct

Ans 2:

Class : Class 7
vbodmas

Ans 3:

Class : Class 10
BODMAS

Ans 4:

Class : Class 9
BODMAS

Ans 5:

Class : Class 9
BODMAS is true.

Ans 6:

Class : Class 8
BODMAS is Brackets Of Division , Multiplication, Addition, Subtraction in Arithmetic :)

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Subject :IMO    Class : Class 3

Ans 1:

Class : Class 6
The predeccesor of 1238769045 is 1238769044.

Ans 2:

Class : Class 5
1238769044

Ans 3:

Class : Class 3
1238769044

Ans 4:

Class : Class 3
1238769044

Ans 5:

Class : Class 3
the predeccesor of 1238769045 is 1238769044

Ans 6:

Class : Class 3
1238769044

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 5
0.12625 ;)

Ans 2:

Class : Class 7
25

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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 6
You got 9.8 marks according to my calculation

Ans 2:

Class : Class 6
The process is: (98/100)×10 Solution: 98/100 = 0.98 So, 0.98×10= 9.8 marks Therefore, you've got 9.8 marks in the paper

Ans 3:

Class : Class 3
9.8

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 7
The three trigonometric functions are : 1. Sin - Opposite over Hypotenuse 2. Cosine - Adjacent over Hypotenuse 3. Tangent - Opposite over Adjacent CLUE - Soh Cah Toa

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Subject :IMO    Class : Class 2

Ans 1:

Class : Class 5
8

Ans 2:

Class : Class 6
8

Ans 3:

Class : Class 5
72

Ans 4:

Class : Class 7
Answer-8

Ans 5:

Class : Class 7
Answer-8

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 8
No, actually there is no easy way to split the middle term. You mainly have do the prime factorisation of the product of coefficient of x2 and the constant, and find its factors which add up to the coefficient of x (the middle term).

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