Subject :IMO Class : Class 6
Subject :IMO Class : Class 6
Ans 1:
Class : Class 6
sum of numbers from 1 to 90 = 90(90+1)/2 = 45 * 91 = 4095
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Subject :IMO Class : Class 4
Ans 1:
Class : Class 7
15
Ans 2:
Class : Class 8
do the opposite calculations.
100/5=20
20+10=30
30/2=15
Ans 3:
Class : Class 8
fifteen/15
Ans 4:
Class : Class 8
15
Ans 5:
Class : Class 4
fifteen\15
Ans 6:
Class : Class 8
15
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Subject :IMO Class : Class 7
Ans 1:
Class : Class 8
BODMAS is correct
Ans 2:
Class : Class 7
vbodmas
Ans 3:
Class : Class 10
BODMAS
Ans 4:
Class : Class 9
BODMAS
Ans 5:
Class : Class 9
BODMAS is true.
Ans 6:
Class : Class 8
BODMAS is Brackets Of Division , Multiplication, Addition, Subtraction in Arithmetic :)
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Subject :IMO Class : Class 3
Ans 1:
Class : Class 6
The predeccesor of 1238769045 is 1238769044.
Ans 2:
Class : Class 5
1238769044
Ans 3:
Class : Class 3
1238769044
Ans 4:
Class : Class 3
1238769044
Ans 5:
Class : Class 3
the predeccesor of 1238769045 is 1238769044
Ans 6:
Class : Class 3
1238769044
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Subject :IMO Class : Class 5
Ans 1:
Class : Class 5
0.12625 ;)
Ans 2:
Class : Class 7
25
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Subject :IMO Class : Class 5
Ans 1:
Class : Class 6
You got 9.8 marks according to my calculation
Ans 2:
Class : Class 6
The process is:
(98/100)×10
Solution:
98/100 = 0.98
So, 0.98×10=
9.8 marks
Therefore, you've got 9.8 marks in the paper
Ans 3:
Class : Class 3
9.8
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Subject :IMO Class : Class 6
Ans 1:
Class : Class 7
The three trigonometric functions are :
1. Sin - Opposite over Hypotenuse
2. Cosine - Adjacent over Hypotenuse
3. Tangent - Opposite over Adjacent
CLUE - Soh Cah Toa
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Subject :IMO Class : Class 2
Ans 1:
Class : Class 5
8
Ans 2:
Class : Class 6
8
Ans 3:
Class : Class 5
72
Ans 4:
Class : Class 7
Answer-8
Ans 5:
Class : Class 7
Answer-8
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Subject :IMO Class : Class 7
Ans 1:
Class : Class 8
No, actually there is no easy way to split the middle term. You mainly have do the prime factorisation of the product of coefficient of x2 and the constant, and find its factors which add up to the coefficient of x (the middle term).