Class : Class 1
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Ans 1: (Master Answer)
Class : Class 1
(D):
A. 4th multiple of 52 = 208
B. 8th multiple of 37 = 296
C. 5th multiple of 25 = 125
D. 7th multiple of 50 = 350
So, 350 is the greatest value amongst all.
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Ans 1:
Class : Class 3
(D):To tip the scale below to the right,the weight ofchocolates should be greater than 37kg.Weight of 5 chocolates =5 x 7=35kgWeight of 6 chocolates=6x7=42kgSo,minimum number of chocolates needed = 6
Ans 4: (Master Answer)
Class : Class 1
(D): To tip the scale below to the right, the weight of chocolates should be greater than 37kg.
Weight of 5 chocolates = 5 x 7 = 35kg
Weight of 6 chocolates = 6 x 7 = 42kg
As, 42kg > 37kg
So, minimum number of chocolates needed = 6
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Ans 3:
Class : Class 10
Nitin , I think you forgot that the sum of the digits of a number should be 9 , As in teh question. All teh other nummbers given by you except 36 is wrong because their digits do nto sum up to 9
Ans 6:
Class : Class 6
The number is not only 36 (It is a number , but there are other numbers) . If you keep x as the ten's digit of the original number and y as the unit's digit of the number , any number following : x 3=y , will follow this rule .The numbers following this rule is 14 27=41 , 25 27=52 , 36 27=63 , 47 27=74 , 58 27=85 , 69 27=96 .
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Ans 1: (Master Answer)
Class : Class 1
(B):
(a) Total number of books in both the libraries = 284683 + 371805
= 656488
(b) Number of more books in second library than the first library = 371805 - 284683
= 87122