International Maths Olympiad Forum By SOF Olympiad Trainer - Page 388
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Prisha Jhunjhunwala from PODAR international, Thane
Subject :IMO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
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Amitava Pushilal from International Schooling, Singapore
Subject :IMO    Class : Class 5

Ans 1:

Neha Samanvita from GIIS TOKYO, Tokyo
Class : Class 5
Cccccccc

Ans 2:

Student from School, City
Class : Class 8
c

Ans 3:

Pratham Dave from GNS, Bangalore
Class : Class 7
C is the answer to this question

Ans 4:

Samreen shams from Ashok Hall Girls higher secondary school , Kolkata
Class : Class 7
c is the correct option

Ans 5:

divish from Delhi Public School, gurgaon
Class : Class 5
c is the correct answer

Ans 6:

Aharshi Kauri from Bishnupur High School, Bishnupur Bankura
Class : Class 7
C

Ans 7:

rethish from Veltech, Avadi
Class : Class 3
C is the correct answer.

Ans 8:

Risha Jakhotiya from Sanskriti School , Pune
Class : Class 3
C is the correct answer

Ans 9: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is option C. 


Ans 10:

divish from Delhi Public School, gurgaon
Class : Class 5
c is the correct answer

Ans 11:

ARADHYA AGARWAL from NEW ERA PROGRESSIVE SCHOOL, Korba
Class : Class 8

Ans 12:

Ashwak from Cambridge, Jalandhar
Class : Class 9
c

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Amitava Pushilal from International Schooling, Singapore
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(D):

A. 4th multiple of 52 = 208
B. 8th multiple of 37 = 296
C. 5th multiple of 25 = 125
D. 7th multiple of 50 = 350
So, 350 is the greatest value amongst all.


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Samiha Grewal from Sat Paul Mittal School, Ludhiana
Subject :IMO    Class : Class 3

Ans 1:

ANIMESH BEHERA from TIMPANY, VISAKHAPATTNAM
Class : Class 3
(D):To tip the scale below to the right,the weight ofchocolates should be greater than 37kg.Weight of 5 chocolates =5 x 7=35kgWeight of 6 chocolates=6x7=42kgSo,minimum number of chocolates needed = 6

Ans 2:

Vivaan Nigam from New Horizon Gurukul, Bangalore
Class : Class 3
its 7

Ans 3:

Nihira Tiwari from Delhi public school electronic city, Bengaluru
Class : Class 6
This question is wrong as 7x9 is 63 and that is also bigger than 37.

Ans 4: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(D): To tip the scale below to the right, the weight of chocolates should be greater than 37kg.
Weight of 5 chocolates = 5 x 7 = 35kg
Weight of 6 chocolates = 6 x 7 = 42kg
 As, 42kg > 37kg
So, minimum number of chocolates needed = 6


Ans 5:

Nihira Tiwari from Delhi public school electronic city, Bengaluru
Class : Class 6

Ans 6:

Ankit from Delhi Public School Megacity Kolkata, KOLKATA
Class : Class 5

Ans 7:

Nihira Tiwari from Delhi public school electronic city, Bengaluru
Class : Class 6
Seee

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Nakul Bhasker from National Public School Whitefield, Bangalore
Subject :IMO    Class : Class 4

Ans 1:

Nakul Bhasker from National Public School Whitefield, Bangalore
Class : Class 5

Ans 2:

Nakul Bhasker from National Public School Whitefield, Bangalore
Class : Class 5

Ans 3:

Sourish from bgs nps, banglore
Class : Class 8
not very difficult

Ans 4:

Wrik Chatterjee from DELHI PUBLIC SCHOOL NOIDA, Noida
Class : Class 5
a

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Soumyajit Roy from Delhi Public School Jamnagar, Jamnagar
Subject :IMO    Class : Class 7

Ans 1:

Kanav Sancheti from JPHS, Jaipur
Class : Class 7
if we read that after walking 3 km she turned right so from west she have turned to go towards north and then she turned left now in which direction she start he journey is north

Ans 2:

Aarav Gupta from Cambridge International School, Jalandhar
Class : Class 5

Ans 3:

Ambar and Adwita from Suncity School, Gurgaon
Class : Class 8

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Yash Bindal from Global Indian International School, Singapore
Subject :IMO    Class : Class 9

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Souraj Saigovindh from Sri chaitanya Techno school, Tirupur
Subject :IMO    Class : Class 7

Ans 1:

Nitin from CHSV, Chennai
Class : Class 6
*x 3=y

Ans 2:

Nitin from CHSV, Chennai
Class : Class 6

Ans 3:

ARUNAV from DPS VINDHYANAGAR, VINDHYANAGAR
Class : Class 10
Nitin , I think you forgot that the sum of the digits of a number should be 9 , As in teh question. All teh other nummbers given by you except 36 is wrong because their digits do nto sum up to 9

Ans 4:

Deepa Jewalkar from Meridian , Hyderabad
Class : Class 7

Ans 5:

Himanshi Singh from BBPS, Gadarwara
Class : Class 9
Correct answer is D.

Ans 6:

Nitin from CHSV, Chennai
Class : Class 6
The number is not only 36 (It is a number , but there are other numbers) . If you keep x as the ten's digit of the original number and y as the unit's digit of the number , any number following : x 3=y , will follow this rule .The numbers following this rule is 14 27=41 , 25 27=52 , 36 27=63 , 47 27=74 , 58 27=85 , 69 27=96 .

Ans 7:

Nitin from CHSV, Chennai
Class : Class 6
The space means addition

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Aaryaman Pradhan from De paul School , Berhampur
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):

(a) Total number of books in both  the libraries = 284683 + 371805
= 656488

(b) Number of more books in second library than the  first library = 371805 - 284683
= 87122


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Asmi Raniga from Indian school Ghubra, Muscat
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(C): Quantity of syrup Mrs. Preeti had = 5 litres = 5000 ml

Quantity of Syrup she poured in each bottle = 300 ml

Number of bottles needed = 5000 ÷ 300 = 16.67
Therefore, 17 bottles are needed. 


Ans 2:

Pranjal from MVN Sector 88, Faridabad
Class : Class 5

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