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Ravi Ranjan Anand from THE AIR FORCE SCHOOL, SUBROTO PARK
Subject :IMO    Class : Class 8

Ans 1:

adityak1135@gmail.com from R.N. Podar School, Mumbai
Class : Class 8
Yes, because of the simple reason, that other polygons have edges! Circle has the same distance from the center at each and every point, whereas the distance from the center to the edges is generally lesser than that to the vertices in other polygons Thus, more area is covered in case of circles.

Ans 2:

OM KANADE from Euro School, Bengaluru
Class : Class 8
yes, it was mentioned in the maths trivia a few days ago. but idk the reason.

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Ishita from Chrysalis high, Bengaluru
Subject :IMO    Class : Class 4

Ans 1:

mohanananda from delhipublicschool, Dhanbad
Class : Class 6
you have to practice atleast 2 to 3 hours in a day maths , follow the syllabus.

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Sunaina Pati from Sarala Birla Gyan Jyoti, Guwahati
Subject :IMO    Class : Class 1

Ans 1:

Ashmita Choudhury from Delhi Public School Noida, Noida
Class : Class 8
22+27=49

Ans 2:

ANWESHA ANVI from DPS Noida, Noida
Class : Class 5
49 is the correct answer

Ans 3:

Admin from admin, Noida
Class : Class 1
It is 49.

Ans 4:

Aryan Sirohi from mount litera zee school, Bengaluru
Class : Class 4
49

Ans 5:

Annantjeet Singh from DPS, Bilaspur
Class : Class 7
22 + 27 = 49

Ans 6:

Pranavk from VIP Bangalore , Bengaluru
Class : Class 5
49

Ans 7:

Rajanya Ghosh from DELHI PUBLIC SCHOOL ELECTRONIC CITY, Bangalore
Class : Class 3
49

Ans 8:

Vasundhara.M from DPS SHARJAH, Dubai
Class : Class 2
22+27=49

Ans 9:

DEVANSHI MALHOTRA from DPS Noida, Noida
Class : Class 5
22+27=49

Ans 10:

Aarush Pathak from Vibgyor High Magarpatta City, Pune
Class : Class 6
49

Ans 11:

Annantjeet Singh from DPS, Bilaspur
Class : Class 7
the answer is 49

Ans 12:

Tanvi Ritisha Dash from delhi public school bangalore east, Bengaluru
Class : Class 6
49

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Sunaina Pati from Sarala Birla Gyan Jyoti, Guwahati
Subject :IMO    Class : Class 1

Ans 1:

Aryan Sirohi from mount litera zee school, Bengaluru
Class : Class 4
49

Ans 2:

Tanvi Ritisha Dash from delhi public school bangalore east, Bengaluru
Class : Class 6
49

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Sunaina Pati from Sarala Birla Gyan Jyoti, Guwahati
Subject :IMO    Class : Class 6

Ans 1:

abhinav from fitjee world school, Hyderabad
Class : Class 8
it may be (a+b)(a-b) so it will be a^2-b^2

Ans 2:

ramesh datta from DPS dwarka , New Delhi
Class : Class 7
what is the full question

Ans 3:

Kusumanchi Vinay from narayana etechno school,madhapur,hyderabad, Hyderabad
Class : Class 6
full question please

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bhargavi from Yuva Bharathi, Singapore
Subject :IMO    Class : Class 7

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ppsk301@gmail.com from Pawar Public School Kandivali, Mumbai
Subject :IMO    Class : Class 5

Ans 1:

Pranav Goyal from Delhi Public School,Noida, Noida
Class : Class 6
Isolation triangle is nothing. It's an isosceles triangle that has 2 sides of equal length.

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mnajl from GEMS New Millennium School Al Khail, Dubai
Subject :IMO    Class : Class 2
c

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VEDIKA AJAY KOTGIRE from TINY ANGELS ENGLISH MEDIUM SCHOOL, Nanded
Subject :IMO    Class : Class 7

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VEDIKA AJAY KOTGIRE from TINY ANGELS ENGLISH MEDIUM SCHOOL, Nanded
Subject :IMO    Class : Class 7

Ans 1:

Sanchay Baranwal from Basava International School, New Delhi
Class : Class 9
The supplements would be- x degree and 2x-45 degree. We all know that two supplements together measure 180 degrees. So, we have- x+2x-45=180 =3x-45=180 =3x=180+45 (On Transposing -45 to RHS becomes+45) =3x=225 =x=225/3 (On Transposing *3 to RHS becomes /3) =x=75 degrees (This is the first angle) So, 2nd angle= 2x-45= 2*75-45= 150-45= 105 degrees On checking, we have 105+75=180 degrees. So greater angle measures 105 degrees.(Answered and proved with explanation).

Ans 2:

Ketan Patil from PAWAR PUBLIC SCHOOL, BHANDUP, Mumbai
Class : Class 8
LET THE GREATER ANGLE BE x SINCE x IS 45 DEGREES LESS THAN TWO TIMES OF ITS SUPPLEMENT THEREFORE x+45=2(180-x) =>x+45=360-2x =>x+2x=360-45 =>3x=315 =>x=315/3 =>x=105 ANS. GREATER ANGLE IS 105

Ans 3:

Pulkit mittal from GAIL DAV PUBLIC SCHOOL, AURAIYA
Class : Class 9
THIS QA IS FROM IMO MTG BOOKLET 11 QA CH4

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