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Subject :IMO    Class : Class 5

Ans 1:

Class : Class 8
Sum of number in each chain is 15.

Ans 2:

Class : Class 3
sum of all numbers in a line is 15 6 4 5=15, 6 3 6=15, 6 8 1=15,7 5 3=15 so Answer is A

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Subject :IMO    Class : Class 1

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
Abfiretv8iuretvu4ebvob4ov87ui4q

Ans 2:

Class : Class 6
its too touch

Ans 3:

Class : Class 6
hihihihihihihihihihiihiihihihiihihihihihihihihihihihihiih

Ans 4:

Class : Class 6
Please respond fast.

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
ÁŠ

Ans 2: (Master Answer)

Class : Class 1

The correct answer is D.


Ans 3:

Class : Class 6
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Ans 4:

Class : Class 7
i don't think so

Ans 5:

Class : Class 7
sir could I get an easier method of solving this question?

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 4
B 6

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Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Class : Class 1

The correct answer is B.

19-6+2=28+?-15

Let the missing number be x.

Then ,19 - 6 + 2 = 28 + x - 15 

=> x = 19 - 6 + 2 - 28 + 15 = (19 + 2 + 15) - (6 + 28) = 36 - 34 = 2


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Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Class : Class 1

The correct answer is B.


There is no pair in the alternate digits starting from 6. 
Answer-(b) Two


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Subject :IMO    Class : Class 5
HI

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Subject :IMO    Class : Class 7

Ans 1: (Master Answer)

Class : Class 1

The correct answer is C.

The line segment joining a vertex of a triangle to the midpoint of its opposite side is called a median of the triangle. 
The perpendicular line segment from a vertex of a triangle to its opposite side is called an altitude of the triangle. 
A triangle has three altitudes and three medians. 


Ans 2:

Class : Class 8
We have to use some common sense Zach (nuts)

Ans 3:

Class : Class 8
There is no "C" you pinhead.They are all "A".

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Subject :IMO    Class : Class 10

Ans 1: (Master Answer)

Class : Class 1

The correct anser is D.

Circumference = 24πm, Width of track= 2 m 

As we know that circumference = 2πr
Therefore, 2πr = 24π

                   r = 12m

Now, Radius of outer circle = Radius of inner circle + Width of the track = 12 m + 2 m = 14 m
Again, Circumference of outer circle = 2πR = 2 X 3.14 X 14 = 88 m 

Hence, the quantity of wire required to surround the path completely is 88 m. 


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