Subject :IMO Class : Class 2
stands for 24,then 
stands for
Subject :IMO Class : Class 5
Ans 1:
Class : Class 7
D
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Subject :IMO Class : Class 8
Ans 1:
Class : Class 8
Let us say that the total sum of weight is x
x/120 = 56
x = 6720
Now, let us say that the number girls is z
We know that the sum of the weight of the girls will be the sum of weight of the boys subtracted from the total sum.Let us say that the sum of weights of boys is y.
So now girls total weight sum will be : 6720-y/z = 50
6720-y = 50z
6720 = 50z + y
6720 - 50z = y(Equation 1)
Total sum of weight of boys will be
y/120 - z = 60
y = 7200 - 60z(Equation 2)
Subtracting both equations(1 and 2) :
y-y = 7200-60z - 6720z + 50z
0 = 480-10z
10z = 480
z = 48
Number of girls is 48.So, the number of boys will be 120-48 = 72
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Subject :IMO Class : Class 2
Ans 1:
Class : Class 7
Ans 2:
Class : Class 4
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Subject :IMO Class : Class 5
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Subject :IMO Class : Class 8
Ans 1:
Class : Class 8
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Subject :IMO Class : Class 6
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Subject :IMO Class : Class 5
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Subject :IMO Class : Class 6
State ‘T’ for true and ‘F’ for false.
(i) Perimeter of equilateral triangle is four times its sides.
(ii) Without using the graph paper, we can find the area of a rectangle.
(iii) Distance covered along the boundary of a closed figure is called its area.
| (i) | (ii) | (iii) | |
| A | T | F | T |
| B | F | T | F |
| C | F | T | T |
| D | F | F | T |