International Maths Olympiad Forum By SOF Olympiad Trainer - Page 274
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Sinchana J R from Ssv hi tech education, Davangere, DAVANAGERE
Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): Distance travelled by bus = 12 km 352 m 
Distance travelled by car = 6 k m 6 m
Distance travelled by walk = 420 m
Total distance travelled = 12 km 352 m  + 6 k m 6 m + 420 m = 18 km 778 m = 18778 m = 18.778 km 


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Kushagra Sah from Bahrain Indian School, Manama Bahrain
Subject :IMO    Class : Class 3

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Shiva Jaiswal from Pidar, Thane
Class : Class 4

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Tanish Patil from symbiosis schools nashik, NASHIK
Subject :IMO    Class : Class 7

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Rupam Das from Krishnanagar High School, NADIA
Subject :IMO    Class : Class 6

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Samriddhi Debnath from Garden High School, Kolkata
Subject :IMO    Class : Class 3

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NOYONIKA BOSE SENGUPTA from Jamnabai Narsee School, Mumbai
Class : Class 7

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S from , JAJAPUR
Class : Class 4
b is the correct awnser

Ans 3:

Medhansh Sachdeva from Deens Academy, Bangalore
Class : Class 5
anser is a

Ans 4:

Anunnakee Banerjee from BBPS NOIDA, NOIDA
Class : Class 6

Ans 5:

Prateeshtha Ghosh from Samhita Academy, Bangalore
Class : Class 8

Ans 6:

Medhansh Sachdeva from Deens Academy, Bangalore
Class : Class 5

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Samriddhi Tripathi from St Joseph's School, Varanasi
Subject :IMO    Class : Class 8

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Ujjwal from Pps, Karnal
Class : Class 8
Answer is C

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SINDHU from DELHI PUBLIC SCHOOL GREATER FARIDABAD, Faridabad
Subject :IMO    Class : Class 6

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sai soumayajeet from kendriya vidyalaya ,puri, puri
Subject :IMO    Class : Class 4

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ANITHRO KESH from BGSNPS, Bangalore
Subject :IMO    Class : Class 4

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Naisha Bhatia from Cambridge court high school, Jaipur
Subject :IMO    Class : Class 4

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Nideesha Sandeep Morajkar from Swami Vivekanand English primary School, Chembur
Class : Class 4

Ans 2:

dveep jain from mindful gurukul, Mumbai
Class : Class 4
Answer is D). How? So let’s hear the question and answers fill in the blanks. • There were 40 children at a party. 14 of them were boys. __P__ fraction of children were girls. • Cost of a teddy bear is of the cost of a doll. If cost of the teddy bear is ₹ 114, then cost of the doll is ₹ __Q__ . • Difference between is __R__. • If then x = __S__. P Q R S A 7/20 76 5/8 1/4 B 13/20 76 7/8 1/4 C 7/20 171 5/8 3/4 D 13/20. 171 7/8 3/4 So the first question is. • There were 40 children at a party. 14 of them were boys. __P__ fraction of children were girls. So the answer is 26/40 or 13/20 because if there are 14 boys out of 40 children then 26 girls out of 40 children answer for the first question is 26/40 or 13/20. So option A) and C) cannot be the answer because they are not equivalent to 26/40 or 13/20. Now let’s hear the second question. • Cost of a teddy bear is of the cost of a doll. If cost of the teddy bear is ₹ 114, then cost of the doll is ₹ __Q__ . So the cost of the doll is ₹171 because cost of a teddy bear is 2/3 cost of a doll And the cost of the teddy bear is also equal to ₹114 so how get answer as ₹171 you have to divide ₹114 by 2 to get 1/3 of cost of the doll and then we ₹57, and then we multiply ₹57 by 3 to get the cost of the doll answer is ₹57 + ₹57 + ₹57 = ₹114 + ₹57 or ₹171. Now the option B) cannot be the answer because it is not equivalent to ₹171. Now you’ll are thinking that why I didn’t show the explanation of questions 3 and 4. I did not show you questions 3 and 4 because there are only 4 options and in answers none of the options none of these as their answers. Hence we have an answer which is D).

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