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VIDHU from DPS NOIDA, NOIDA
Subject :IMO    Class : Class 4

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nnautiyal from DPS, DELHI
Subject :IMO    Class : Class 6

Ans 1:

AKSHAT AGRAWAL from NPS, BANGALORE
Class : Class 7

Ans 2:

nnautiyal from DPS, DELHI
Class : Class 6

Ans 3:

AKSHAT AGRAWAL from NPS, BANGALORE
Class : Class 7

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Yash Patel from BHIS, Mumbai
Subject :IMO    Class : Class 8

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Dhairya Godbole from KLE Eng Medium School, SOLAPUR
Subject :IMO    Class : Class 6

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Dhairya Godbole from KLE Eng Medium School, SOLAPUR
Subject :IMO    Class : Class 6

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Ashwin Shridhar from Vidyashilp Academy, Bangalore
Subject :IMO    Class : Class 8

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Harshvardhan Lugade from Podar International School, Pune
Subject :IMO    Class : Class 6

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Advik singla from Pkr Jain vatika sr sec school, Ambala city
Subject :IMO    Class : Class 3

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Ketaki Subhash Ghatol from CSA Satara, Satara
Subject :IMO    Class : Class 8

In the given question, two rows of numbers are given. Resultant number in each row is to be worked out separately based on the following rules and the question below the rows of numbers is to be answered. The operations of numbers progress from left to right.
Rules:
1. If an even number is followed by a prime number, they are to be multiplied.
2. If an even number is followed by a composite odd number, odd number is to be subtracted from the even number.
3. If an odd number is followed by a prime number, the first number is to be divided by the second number.
4. If an odd number is followed by an even number which is a perfect square, they are to be added.
5. If an odd number is followed by composite odd number, they are to be added.
23 15 9 64
x 31 15 3
If x is the resultant of the first row, then what is the resultant of the second row?

A54
B18
C21
D72


Ans 1:

Arnav Diwan from F.A.I.P.S Kuwait, Kuwait
Class : Class 7
simple solution Sol: so, in the first row we have 23 15 9 64 23 plus 15 = 38 (applied rule 5) 38 - 9 = 29 (applied rule 2) 29 plus 64 = 93 (applied rule 4) Hence, First row result is 93 which is equivalent to x So, now in the second row we have 93 31 15 3 93 divided by 31 = 3 (applied rule 3) 3 plus 15 = 18 (applied rule 5) 18 X 3 = 54 (applied rule 1) Hence, resultant of second row is 54 which is answer option A

Ans 2:

KRISHNASHREE SWAIN from DELHI PUBLIC SCHOOL RAIPUR, RAIPUR
Class : Class 8

Ans 3:

Dhairya Vinayak from Loyola High School, Patna
Class : Class 8

Ans 4:

Arnav Diwan from F.A.I.P.S Kuwait, Kuwait
Class : Class 7
simple solutionSol: so, in the first row we have 23 15 9 6423 15 = 38 (applied rule 5)38 - 9 = 29 (applied rule 2)29 64 = 93 (applied rule 4)Hence, First row result is 93 which is equivalent to xSo, now in the second row we have 93 31 15 393 divided by 31 = 3 (applied rule 3)3 15 = 18 (applied rule 5)18 X 3 = 54 (applied rule 1)Hence, resultant of second row is 54 which is answer option A

Ans 5:

Rithanya S from KV NAL, Bengaluru
Class : Class 8
Can someone solve this question

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Diya from delhi public school dlf phase-2, GURUGRAM
Subject :IMO    Class : Class 6

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