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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 7
Solution and explanations please....

Ans 2:

Class : Class 8

Ans 3:

Class : Class 7
Actually, it was a pretty simple problem.1. Divide 1901 by 6 (which is equal to 316)2. Since there is a remainder, 317(316 1) times 6 gives you the first number divisible by 6 within the range.3. Next, divide 2000 by 6 (which is 333), similarly, 333 times 6 gives you the last number divisible by 6 within this range.The answer is 17 not 16 because there are 17 numbers which are divisible by 6: -317, 318, 319, 320, 321, 322, 323, 324, 325, 326, 327, 328, 329, 330, 331, 332, 333Hope this is helpful.Thanks

Ans 4:

Class : Class 8

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 8
i think the answer is 10u as- breadth=u so length=4u perimeter=2(l+b)=2(4u+u)==2*5u=10u

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 6

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 5

Ans 2:

Class : Class 4
garima and megha,after calculation

Ans 3:

Class : Class 4
garima and megha

Ans 4:

Class : Class 5
garima

Ans 5:

Class : Class 3
Garima and Megha

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Subject :IMO    Class : Class 7

Ans 1:

Class : Class 7

Ans 2:

Class : Class 6

Ans 3:

Class : Class 7

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Subject :IMO    Class : Class 9

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Subject :IMO    Class : Class 4

Ans 1:

Class : Class 3
explain

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Subject :IMO    Class : Class 6

Ans 1:

Class : Class 6
Answer should be C

Ans 2:

Class : Class 6
ANS IS

Ans 3:

Class : Class 7
c -- (3x - 6) years

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Subject :IMO    Class : Class 5

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