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Ashwin Shridhar from Vidyashilp Academy, Bangalore
Subject :IMO    Class : Class 8

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Harshvardhan Lugade from Podar International School, Pune
Subject :IMO    Class : Class 6

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Advik singla from Pkr Jain vatika sr sec school, Ambala city
Subject :IMO    Class : Class 3

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Ketaki Subhash Ghatol from CSA Satara, Satara
Subject :IMO    Class : Class 8

In the given question, two rows of numbers are given. Resultant number in each row is to be worked out separately based on the following rules and the question below the rows of numbers is to be answered. The operations of numbers progress from left to right.
Rules:
1. If an even number is followed by a prime number, they are to be multiplied.
2. If an even number is followed by a composite odd number, odd number is to be subtracted from the even number.
3. If an odd number is followed by a prime number, the first number is to be divided by the second number.
4. If an odd number is followed by an even number which is a perfect square, they are to be added.
5. If an odd number is followed by composite odd number, they are to be added.
23 15 9 64
x 31 15 3
If x is the resultant of the first row, then what is the resultant of the second row?

A54
B18
C21
D72


Ans 1:

Rithanya S from KV NAL, Bengaluru
Class : Class 9
Can someone solve this question

Ans 2:

Dhairya Vinayak from Loyola High School, Patna
Class : Class 8

Ans 3:

Arnav Diwan from F.A.I.P.S Kuwait, Kuwait
Class : Class 10
simple solutionSol: so, in the first row we have 23 15 9 6423 15 = 38 (applied rule 5)38 - 9 = 29 (applied rule 2)29 64 = 93 (applied rule 4)Hence, First row result is 93 which is equivalent to xSo, now in the second row we have 93 31 15 393 divided by 31 = 3 (applied rule 3)3 15 = 18 (applied rule 5)18 X 3 = 54 (applied rule 1)Hence, resultant of second row is 54 which is answer option A

Ans 4:

KRISHNASHREE SWAIN from DELHI PUBLIC SCHOOL RAIPUR, RAIPUR
Class : Class 8

Ans 5:

Arnav Diwan from F.A.I.P.S Kuwait, Kuwait
Class : Class 10
simple solution Sol: so, in the first row we have 23 15 9 64 23 plus 15 = 38 (applied rule 5) 38 - 9 = 29 (applied rule 2) 29 plus 64 = 93 (applied rule 4) Hence, First row result is 93 which is equivalent to x So, now in the second row we have 93 31 15 3 93 divided by 31 = 3 (applied rule 3) 3 plus 15 = 18 (applied rule 5) 18 X 3 = 54 (applied rule 1) Hence, resultant of second row is 54 which is answer option A

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Diya from delhi public school dlf phase-2, GURUGRAM
Subject :IMO    Class : Class 6

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Kunal Kankani from Bharti Public School, Delhi
Subject :IMO    Class : Class 3

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Aayush Tripathy from SAI International School, Bhubaneswar
Subject :IMO    Class : Class 6

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Esha Parnami from Greenwood high Bangalore , Bangalore
Class : Class 3

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Sanay Pathak from Hooghly, Hooghly
Class : Class 5

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Kunal Kankani from Bharti Public School, Delhi
Subject :IMO    Class : Class 3

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soumik mitra from vwms, mankundu
Class : Class 3
7

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Megh Dutt from BHAVAN'S RAJAJI VIDYASHARAM, CHENNAI
Subject :IMO    Class : Class 6

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Megh Dutt from BHAVAN'S RAJAJI VIDYASHARAM, CHENNAI
Class : Class 6

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pravin dharsaun from maharishi vidya mandir, CHENNAI
Subject :IMO    Class : Class 10

Read the following information carefully to answer the given question.
Fifty books belonging to different subjects, viz. History (8), Geography (7), Literature (13), Psychology (8) and Science (14), are placed on a shelf. They are arranged in an alphabetical order subject to the condition that no two books of the same subject are placed together so long as books of other subjects are available. Unless otherwise mentioned, all counting is done from the left.
Counting from the right end, the fifth book from the right of 39th book is ______.

AHistory
BPsychology
CGeography
DScience


the 12 th book from left should be the 39 th book from right so answer is psychology

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