Class : Class 7
Then the calculation will turn to 20 +8/4x3x2,
=20+2x3x2,
=20+6x2,
=20+12
=32,
so there is a problem in the question
Class : Class 8
the division sign represents both addition and subtraction and we can get to different answers
Class : Class 6
There is problem in the Q as it mentions division sign represents both addition and substraction
Class : Class 9
WHY ARE YOU CONFUSING US AND WHY ARE YOU NOT PROVIDING CORRECT QUESTIONS AND WHY ARE YOU MAKING US LOSE OUR MARKS???????? SOF this is WRONG!!!!!!!!!!!!!!!!!
Class : Class 9
This question is not correct, as the division symbol is used for both addition and subtraction.
Class : Class 7
yes please correct. There are 2 division signs which represent addition n subtraction which leads to various answers
Class : Class 8
The divisions sign is used in 2 places, but I think it means subtraction because '-' meaning subtraction is not exactly coding anything...And in that case 20 8/4-3x2=20 2-6=16...Which is not an options for whatever weird reason
Class : Class 8
answer should be 16 as - coded for subtraction doesn't really code anything so it is 22-6=16
Class : Class 9
How can you change 2 to 3? and how can you mark division symbol as addition and subtraction? SOF DON'T DO SUCH MISTAKES OR WE'LL HAVE TO REPORT IT TO sofworld.org
Ans 1: (Master Answer)
Class : Class 1
The correct answer is C.
In ΔAED,
∠AE D + ∠EAD + 90° = 180° (Angle sum property)
⇒ ∠AED + ∠EAD = 90°
⇒ ∠EAD = 90° – ∠AED ...(i)
Also, ∠EAD = (50° + ∠AFB) ...(ii) (Exterior angle property)
From (i) and (ii), we have
50° + ∠AFB = 90° – ∠AED
⇒ ∠AFB + ∠AED = 90° – 50° = 40°
⇒ ∠AED + ∠CFD = 40°
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Ans 5:
Class : Class 6
The first and third letters are interchanged, and their immediate next letter is taken. The 2nd, 4th and 6th letter are directly written without any change. Same happens to 5th and 7th letters. This is the pattern here.
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Ans 3:
Class : Class 3
First option is wrong because a parallelogram is not always necessary to be a square or a rectangle ,as they only have diagonals equal.
Second option is wrong because rectangle does not follow this property which can be checked by using SAS congruence criteria.
Third option is wrong because if the diagonals of a quadrilateral intersect at right angles then it is necessarily a rhombus, if u are thinking that square also have this property then add up a point that every square is a rhombus.
Fourth option is wrong because every quadrilateral is not necessarily be a trapezium, a parallelogram or a kite as concave quadrilaterals are none of them.
Ans 6:
Ans 8:
Class : Class 10
third option is correct since in a kite, diagonals intersect at right angles and kite is not a rhombus. it does not talk about bisecting.