National Science Olympiad Forum By SOF Olympiad Trainer - Page 591

User Forum

Subject :NSO    Class : Class 6

Ans 1:

Class : Class 9
It is A

Ans 2:

Class : Class 7
ANSWER SHOULD BE C BECAUSE FIRRST IS CORRECT BUT METALS ARE GOOD CONDUCTERS OF HEAT

Ans 3:

Class : Class 9

Ans 4:

Class : Class 6
I too agree with you .It's B and not A

Ans 5:

Class : Class 6
it cannot be as you have said because the wax is dripping from the glass rod whereas on the copper rod, it is as it was first placed. And they will not give us a diagram if they are going to ask something not related to it.So, the answer must be B and not A.

Ans 6:

Class : Class 3
the wax has been applied all over the rod. copper has the least amount of wax on it. So it is the best conductor of heat whereas the glass rod has the most amount of wax thus it is the weakest conductor of heat.Thus,the option "A" is the correct answer

Ans 7:

Class : Class 6

Ans 8:

Class : Class 6
what is this man do something

Ans 9:

Class : Class 6
IT WILL BE DDDDDDDDDDDDDDDDDDD

Ans 10:

Class : Class 9
ACCORDING TO ME THE CORRECT ANSWER IS B , FIRST WE HAVE TO UNDERSTAND THE PICTURE AND THEN ANSWER

Ans 11:

Class : Class 8
b is the answer

Ans 12:

Class : Class 9
It must be 'B' not 'A'

Ans 13:

Class : Class 6
Sorry for giving the wrong information. At the beginning even I thought the answer was B.If you click the solution button, it says that since the copper rod has the least amount of wax on it, it is the better conductor as all the other wax on it has melted and fell down. That is why the answer is A not B

Ans 14:

Class : Class 7

Ans 15:

Class : Class 7
The answer is 'a' because the rods are fully coated with wax, those rods which have less wax are good conductors because the wax melted and fell from it.

Ans 16:

Class : Class 8

Ans 17:

Class : Class 7

Ans 18:

Class : Class 8
OK

Ans 19:

Class : Class 8
why is everyone talking about wax and copper it is a question about statements and conductivity like bruh what

Ans 20:

Class : Class 7
dddddddddddddddddddddddd

Post Your Answer

Subject :NSO    Class : Class 1

Post Your Answer

Subject :NSO    Class : Class 8

Ans 1:

Class : Class 8
In my opinion, the answer should be both option (C) and option (D). Transverse waves are waves in which the motion of particles are perpendicular to the motion of the wave (for example, light). Moving the slinky at an angle of 45 degrees to the table would create a wave, just not a perpendicular one, and thus not a transverse wave. This excludes option (A). Option (B) is also excluded, as it creates a longitudinal wave (motion of the particles is parallel to the motion of the wave). Option (C) involves the wave being moved up and down (assumed to be at right angles, since it is not mentioned). The slinky thus also moves up and down, and creates a transversal wave (as the motion of the wave is from Q to P, and the motion of the parts of the slinky is perpendicular to line QP). Option (C) is thus correct. Option (D) involves the wave being moved left to right (assumed to be at right angles, since it is not mentioned). This also created a transverse wave (as the motion of the parts of the slinky is perpendicular to the motion of the wave from Q to P). Option (D) is thus, also correct. Since we live in a three dimensional world, and it is not mentioned in the question that the experiment is performed in a 2 dimensional world, we can assume that the experiment is done in a 3D world. Due to the presence of length, breadth and height, the slinky can be moved in two ways perpendicular to line QP (i.e. the slinky). Given that both ways this can be done are mentioned in the question, both options must be correct. Therefore, I opine that the correct answer is both option (C) and option (D).

Ans 2: (Master Answer)

Class : Class 1

The correct answer is D

In transverse wave, vibration of a wave is perpendicular to its direction of propagation of wave.


Ans 3:

Class : Class 8
Won't moving the slinky up and down produce the same result? You can check b observing from the side.

Ans 4:

Class : Class 6

Ans 5:

Class : Class 8

Ans 6:

Class : Class 8

Ans 7:

Class : Class 7

Ans 8:

Class : Class 9

Ans 9:

Class : Class 9
The correct answer is D. In a transverse wave the direction of the movement of the particle is perpendicular to direction of motion of the wave. So, over here, when we move the end Q from left and right , it will produce a transverse wave,. You can check it by observing it from the top.

Ans 10:

Class : Class 9

Post Your Answer

Subject :NSO    Class : Class 7

Ans 1: (Master Answer)

Class : Class 1

The correct answer is A.

Sugar syrup is neutral and hence the colour of blue litmus and red litmus remains unchanged. Tamarind juice is acidic, so blue litmus turns red but red litmus does not change its colour. Lime water and soap solution are basic in nature which turn red litmus blue whereas blue litmus remains unchanged.


Ans 2:

Class : Class 9
Answer is A

Ans 3:

Class : Class 9
yeah the answer is a

Ans 4:

Class : Class 8

Ans 5:

Class : Class 8

Post Your Answer

Subject :NSO    Class : Class 7

Ans 1: (Master Answer)

Class : Class 1

Fish Y will be least affected as it is camouflaging with the sea weeds. Fish Y can easily escape from the predator by blending with the surrounding environment.


Post Your Answer

Subject :NSO    Class : Class 7

Ans 1:

Class : Class 6
b is the correct answer

Ans 2:

Class : Class 7
i think b is the correct answer

Ans 3:

Class : Class 7
B is the correct answer

Ans 4:

Class : Class 10
Also freezing and melting point of water is 0 degrees celsius

Ans 5:

Class : Class 9
B should be the correct answer I think

Ans 6:

Class : Class 8
at 4 degree celsius water starts expanding and 'x' shows the same the room temperature might have been near or equal to the freezing point of water(eg room temperature of regions like arctic and antarctic)

Ans 7:

Class : Class 7
either b or d

Ans 8:

Class : Class 10
why?

Ans 9:

Class : Class 7
I think B is the correct answer because there is no solidification taking place or else the water would have turned into ice. plus no solidification can take place when water is at room temperature.

Ans 10:

Class : Class 8
I THINK THAT B IS ONLY THE CORRECT ANSWER

Ans 11:

Class : Class 7

Ans 12:

Class : Class 10
i think there is no option correct in this ques. no evaporation and boiling is taking place as it is cooling down towards the room temperature. also no condensation is taking place as in the ques it is written a HOT liquid is being transferred to a beaker. as well as solidification may also not take place because room temp is above 0 degree centigrate. SOF PLEASE SEE TO IT THAT THIS TYPE OF WRONGG QUESTIONS AND SOLUTIONS ARE NOT POSTED.

Ans 13:

Class : Class 7
i think b is the correct answer

Ans 14:

Class : Class 7
There is no proper solution for this question which will make it more confusing as everyone will have different opinions in this question.

Ans 15:

Class : Class 8
I think b is correct because there is no solidification

Ans 16:

Class : Class 8
It is cooling towards room temperature so it does not solidify since the freezing point is below room temperature.

Ans 17:

Class : Class 9
i think b is correct

Ans 18:

Class : Class 7
Three states - gas , liquid & solid When hot water temp is going down it will be ultimate become solid ie ice But before becoming ice temp will stagnant for some time where in both states liquid & solid co-exist==> some part of liquid is in ice form. X is the same state where in solid and liquid will co-exist. Hence option 4 is correct(solidification& evaporation) Note: Could not attach gif .It would have made it more clear.

Ans 19:

Class : Class 10
It cools towards room temperature so it does not freeze

Post Your Answer

Subject :NSO    Class : Class 3

Ans 1:

Class : Class 4
The answer is gibbous moon.

Ans 2:

Class : Class 4
b

Ans 3:

Class : Class 4
Gibbons moom

Ans 4:

Class : Class 9

Ans 5:

Class : Class 4
3 Class

Ans 6:

Class : Class 3

Ans 7:

Class : Class 4
Ug

Ans 8:

Class : Class 5
b

Ans 9:

Class : Class 5
okkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

Ans 10:

Class : Class 4
3

Post Your Answer

Subject :NSO    Class : Class 4

Ans 1:

Class : Class 9
A

Ans 2:

Class : Class 9
A

Ans 3:

Class : Class 5
a

Ans 4:

Class : Class 8
a is right

Ans 5: (Master Answer)

Class : Class 1

The correct answer is A.

Both plants ‘c’ and ‘d’ bear fruits. This means they are flowering plants as only flowers change into fruits. Plant ‘c’ grows in water i.e., it is an aquatic plant but plant ‘d’ does not grow in water thus, it is a nonaquatic plant. Hence 'W' and 'X' represent plant ‘c’ and ‘d’ respectively.


Ans 6:

Class : Class 4
Yes. A.

Post Your Answer

Subject :NSO    Class : Class 8

Ans 1:

Class : Class 8
It’s not mentioned about tightness of the circuits.

Ans 2: (Master Answer)

Class : Class 1

The correct answer is B

In given figures, both the circuits are tightly connected and both the liquids conduct electricity because both the bulbs are glowing. The bulb in the set up P glows more brightly as compared to that of the set up Q might be because of any of the two possibilities:

1. The liquid in Q may have small conductivity. 

2.  Liquid in P is equivalent to a battery while liquid in Q is equivalent to a cell of the battery of liquid P


Ans 3:

Class : Class 9
but how do we know that the circuit is conneced tightly???

Ans 4:

Class : Class 8
Yes.. Tightness is not mentioned.

Ans 5:

Class : Class 8
How can a liquid be equal to a battery and another liquid be equal to *its* cell?

Ans 6:

Class : Class 10

Ans 7:

Class : Class 9

Ans 8:

Class : Class 8
How can a liquid be equal to a battery and another liquid be equal to *its* cell?

Post Your Answer

Subject :NSO    Class : Class 4
Hi

Ans 1: (Master Answer)

Class : Class 1

Plaese mention your query


Post Your Answer