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Mannat Verma from Vivek High School , Chandigarh
Subject :NSO    Class : Class 4

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is A.

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Devang Bansal from St Kabir Public School, Chandigarh
Subject :NSO    Class : Class 9

Ans 1:

Yogesh Agrawal from Netizens IIT JEE Foundation , Latur
Class : Class 9
the wave length in air by v=n.lemda, so 350 = 700 . wavelength so wave length = 0.5 m Now when it enters in brass, v = 3500 m/s, so new wavelength = 3500 / 700 = 5 m. So answer is option A, i.e. wavelength will be increased by a factor of 10.

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Devang Bansal from St Kabir Public School, Chandigarh
Subject :NSO    Class : Class 9

Ans 1:

Kokilavani K from Vaels International School, Chennai
Class : Class 9

Ans 2:

Rikhil Gupta from Christ Academy, Bengaluru
Class : Class 9
lets go column wise(up to down) in the first one, the topmost value is 7. if we multiply this value with the second last value(i.e. 3), we get 21. now we must add this 21 with the second term(i.e. 8), and we get the last term that is 29. follow the same logic

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Ayana Garg from Universal High Dahisar, Mumbai
Subject :NSO    Class : Class 3

Ans 1:

Angshu Ray from DPS East, Bangalore
Class : Class 4

Ans 2:

Angshu Ray from DPS East, Bangalore
Class : Class 4
sorry it is B . My mistake

Ans 3:

Angshu Ray from DPS East, Bangalore
Class : Class 4
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Ans 4: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is B.

Ans 5:

Angshu Ray from DPS East, Bangalore
Class : Class 4

Ans 6:

Neelesh Dutta from Innocent Hearts School, JALANDHAR
Class : Class 5
We all know that the correct answer is B . It's not the Master Answer !!!!!

Ans 7:

Angshu Ray from DPS East, Bangalore
Class : Class 4
the correct answer is A according to the pattern

Ans 8:

Angshu Ray from DPS East, Bangalore
Class : Class 4

Ans 9:

Neelesh Dutta from Innocent Hearts School, JALANDHAR
Class : Class 5
We all know the answer is B . It's not the Master Answer !!!!

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tanmay from amaatra academy, bangalore
Subject :NSO    Class : Class 5

Ans 1:

Rishita Verma from Suncity School, Gurgaon
Class : Class 5

Ans 2:

SOURADEEP SHARMILA MANDAL from KENDRIYA VIDYALAYA IISC, Bengaluru
Class : Class 6
you are right it is 13 days not 14 (I too made the same mistake)

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Saina from DPS, Noida
Subject :NSO    Class : Class 4

Ans 1:

shalini mittal from DPS Greater Noida, Greater noida
Class : Class 4

Ans 2:

Abhineet Nandy from DPS Whitefield, Bangalore
Class : Class 4
The answer is [D] None of these, because the picture shows Kimono which is the traditional dress of Japan

Ans 3:

Abhinav Kulkarni from National Centre For Excellence, Bengaluru
Class : Class 4

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Pranav Kannan from Phoenix Greens, Hyderabad
Subject :NSO    Class : Class 3

The given figure shows phases of the Moon as seen from the Earth surface (as shown with arrow point). The following statements describe the lunar cycle. Select the correct statement(s).

(1) The lunar phases progress from Full Moon, Crescent Moon, First Quarter Moon, Gibbous Moon and New Moon, before returning through Gibbous Moon, last Quarter Moon, Crescent Moon and Full Moon.
(2) From phase 1 to 3 waxing crescent is seen and from phase 7 to 9 waning crescent is seen.
(3) From phase 3 to 5 waxing gibbous is seen and from phase 5 to 7 waning gibbous is seen.
(4) 50% illuminated Moon is seen in phase '3' as well as in phase '7'.

A 1 only
B 1 and 3
C 1, 2 and 4
D 2, 3 and 4


d is the answer

Ans 1:

Aditya singh from Dps greater Noida, Greater Noida
Class : Class 3

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
The correct answer is D.

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Pranav Kannan from Phoenix Greens, Hyderabad
Subject :NSO    Class : Class 3

Ans 1:

Pranav Kannan from Phoenix Greens, Hyderabad
Class : Class 3
c

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Gulzar Russell from Kendriya Vidyalaya No.1, Calicut
Subject :NSO    Class : Class 8

Ans 1:

AAshutosh Jindal from HOLY angels school, RAJPURA
Class : Class 8
The ans is A,B

Ans 2:

Harshit from Army Public School, Lucknow
Class : Class 9
Hi friend. The ans is (A) amplitude of vibrating body. HOPE THIS HELPS!!!!

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Soumyaranjan Nath from Delhi Public School , Angul
Subject :NSO    Class : Class 9

Ans 1:

divanshi from sacred heart convent school, barnala
Class : Class 9
I AM NOT ABLE TO UNDERSTAND THE SOLUTION

Ans 2:

Adwyth G Nair from Chinmaya Vidyalaya Tripunithura, Kochi
Class : Class 8
as momentum is conserved, m1v=(mi m2)3/2v mi=(m1 m2)3/2 ( mutiply both sides )by rearranging and substituting 3m1=m2 the i got is 9

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