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Abhineeth Maity from Bright Riders School, Abu Dhabi
Subject :NSO    Class : Class 9

Which of the following statements about the given experimental set-up is/are incorrect?

I. It is used to separate a mixture of two or more miscible liquids for which the difference in boiling points is more than 25 K.
II. It is used for the separation of different gases from air.
III. It is used to separate acetone and water from their mixture.
IV. It is based on the principle of repeated cooling and condensation of vapours by providing surface for the vapours.

A I only
B III and IV only
C I and II only
D I and III only


Ans 1:

Gokulakrishnan from Rosemary public school, Tirunelveli
Class : Class 9
3 and 1 only

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Aniket Hedde from Podar International School, Nanded
Subject :NSO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is D

The electonic configuration of manganese (atomic number=25) is 1s2 2s2 2p6 3s2 3p6 3d5 4s2


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Neha Sharma from St Patricks, Gurgaon
Subject :NSO    Class : Class 4

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Ayush sharma from GEMS international school , Gurgaon
Subject :NSO    Class : Class 6

Which of the following statements is correct ?
(i) The response of plant towards the Earth is called phototropism .
(ii) The ability of certain animals to blend with the surrounding, making them difficult to spot is called camouflage.
(iii) Whales and dolphins breathe in oxygen from water through gills.
(iv) Hibernation is an adaptation for escaping hot weather.

A(i) and (ii)
B(ii) and (iv)
C(i) and (iv)
D(iii) and (iv)


escaping hot weather is called aestivation . hibernation is escaping from cold weather .

Ans 1:

Manvi Mundepi from Montfort School Roorkee, Roorkee
Class : Class 7
I WANT EXPLAINATION

Ans 2:

MInnal Senthil from Prakriya, Bangalore
Class : Class 5
not a because The response of plant towards the sun is called phototropism

Ans 3:

santosh katiyar from narayana vidhyalayam, Nagpur
Class : Class 7
THE CORRECT ANSWER IS (A)

Ans 4:

Dipam from Podar International School, Aurangabad
Class : Class 8
YES The correct answer is (A).

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VAIBHAV KALVAKOTA from THE LEXICON INTERNATIONAL SCHOOL WAGHOLI, PUNE
Subject :NSO    Class : Class 8

Ans 1:

VAIBHAV KALVAKOTA from THE LEXICON INTERNATIONAL SCHOOL WAGHOLI, PUNE
Class : Class 8

Ans 2:

Anirudh from Kendriya Vidyalaya Kanjikode, Palakkad
Class : Class 8
All the properties friction are in use. Hence, the correct one option 'D'.

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VAIBHAV KALVAKOTA from THE LEXICON INTERNATIONAL SCHOOL WAGHOLI, PUNE
Subject :NSO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is C.


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shaurya chitriki from delhi public school north, bangalore
Subject :NSO    Class : Class 3

Ans 1:

Mohi from Vibgyor, Bangalore
Class : Class 4
B) 2 and 3

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Dheeraj from Sri Sri Ravishankar Vidya Mandir, Bangalore
Subject :NSO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

Mass is the amount of matter present in an object whereas weight is the force exerted by the gravity on that object.

Now, the weight of an object, W = g X m, where 'g' is Earth's gravitational constant and 'm' is the mass of the object.

The weight of the object will remain constant as long as the mass of that object is not changing since 'g' is constant. However, the weight of an object can still be changed without changing the mass. This can be explained by the following example: Consider a helicopter with a mass, 'm'.

1. If the helicopter is accelerated towards the earth (during landing) with an acceleration equals to 'A' (positive acceleration) then its weight would become, W = (g + A) X m,  and hence, the weight would increase.

2.  If the helicopter is accelerated away from the earth (during take-off) with an acceleration equals to '- A' (negative acceleration) then its weight would become, W = (g - A) X m,  and hence, the weight would decrease.


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Dheeraj from Sri Sri Ravishankar Vidya Mandir, Bangalore
Subject :NSO    Class : Class 7

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

Mass is the amount of matter present in an object whereas weight is the force exerted by the gravity on that object.

Now, the weight of an object, W = g X m, where 'g' is Earth's gravitational constant and 'm' is the mass of the object.

The weight of the object will remain constant as long as the mass of that object is not changing since 'g' is constant. However, the weight of an object can still be changed without changing the mass. This can be explained by the following example: Consider a helicopter with a mass, 'm'.

1. If the helicopter is accelerated towards the earth (during landing) with an acceleration equals to 'A' (positive acceleration) then its weight would become, W = (g + A) X m,  and hence, the weight would increase.

2.  If the helicopter is accelerated away from the earth (during take-off) with an acceleration equals to '- A' (negative acceleration) then its weight would become, W = (g - A) X m,  and hence, the weight would decrease.


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ansh rai from delhi public school, Bhilai
Subject :NSO    Class : Class 5

Ans 1:

Poulami Dan from Aditya Academi, Kolkata
Class : Class 5
c

Ans 2:

shreedhar from the shri ram school, delhi
Class : Class 5
mechanical,kinetic (c)

Ans 3:

Niveideeta Cour from Suncity World School, Gurgaon
Class : Class 5
mechanical into kinectic

Ans 4:

RISHABH from SUMMER FIELD, GURGAON
Class : Class 5
c

Ans 5:

Shreetej from Pearson public school, Pune
Class : Class 5
Its option (c), mechanical into kinetic

Ans 6:

shaurya aggarwal from scholars rosary senior secondary school, rohtak
Class : Class 4
Mechanical,kinetic

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