Read the given statements and select the correct option.
Statement I : Jute is used to make containers for young saplings that can be planted directly.
Statement II :Jute cannot be easily decomposed by microorganisms.
ABoth statements I and II are true and statement II is the correct explanation of statement I.
BBoth statements I and II are true but statement II is not the correct explanation of statement I.
CStatement I is true but statement II is false.
DBoth statements I and II are false.
Match the column I with column II and select the correct option from the given codes.
AP - 3, Q - 4, R - 1, S - 2
BP - 4, Q - 3, R - 2, S - 1
CP - 3, Q - 4, R - 2, S - 1
DP - 4, Q - 3, R - 1, S - 2
Study the arrangement of four magnets shown in the given diagram. Which of the following is a possible arrangement of two of the magnets?
Ans 1: (Master Answer)
As we know, opposite poles of magnets attract each other. Then the possible combinations can be :
P - North, Q - South, R - North, S - South, T - North, U - South, V - North, W - South
P - South, Q - North, R - South, S - North, T - South, U - North, V - South, W - North
Lets say if Q is S - South. Then, the only possible option is (B).
“Do not handle electric wires with your bare hands. Wear rubber gloves,” said Mr Gupta. Which of the following statements is not true about what Mr. Gupta commented?
A You will get electrocuted if you handle live wires.
B The rubber glove is a good insulator to protect us from electric shocks.
C The rubber gloves control the electric current flow.
D Electricity cannot flow through rubber.
Observe the given figures showing different methods of separation carefully and select the correct statements.
I. Method 1 is generally used to obtain pure water from muddy water.
II. Method 2 is used to separate components of a mixture which are miscible with each other and have different densities.
III. Method 3 is generally used to separate pulp from fresh fruit juice.
IV. Method 1 is based on the difference in boiling points of immiscible liquids while method 3 is based on the difference in size of components of a solid-solid mixture.
A(I) and (IV) only
B(II) and (III) only
C(II) and (IV) only
DNone of these
Match column I with column II and select the correct option from the given codes.
|Column I||Column II|
|T.||Density (= mass ÷ volume)||(v)||kg/m3|
AP-(i), Q-(ii), R-(iii), S-(iv), T-(v)
BP-(iv), Q-(iii), R-(ii), S-(v), T-(i)
CP-(iii), Q-(i), R-(iv), S-(ii), T-(v)
DP-(iii), Q-(i), R-(ii), S-(iv), T-(v)
Consider the following list of materials to answer the question which follows.
I. Liquid oxygen
II. Soap solution
Which one of the following is correct?
AI, III and IV are elements.
BII, III and V are mixtures.
CIII and IV are elements.
DIII and V are compounds.
Isn t soap solution aka sodium hydroxide a co,pound