National Science Olympiad Forum By SOF Olympiad Trainer - Page 843
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A Andrew from Lalaji Memorial Omega International School, Chennai
Subject :NSO    Class : Class 4

Ans 1: (Master Answer)

from ,
Class :
The correct answer is C.

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A Andrew from Lalaji Memorial Omega International School, Chennai
Subject :NSO    Class : Class 4

Ans 1:

from ,
Class :
B

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A Andrew from Lalaji Memorial Omega International School, Chennai
Subject :NSO    Class : Class 4

Ans 1: (Master Answer)

from ,
Class :
The correct answer is B.

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jeeva from Kendriya Vidyalaya Kottayam, Kottayam
Subject :NSO    Class : Class 7

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from ,
Subject :NSO    Class : Class 3

Ans 1:

Kavin Karthick M from DPS bangalore east, Bengaluru
Class : Class 6
BOTH MASS AND LENGTH SHOULD BE SAME.

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from ,
Subject :NSO    Class : Class 3

Ans 1: (Master Answer)

from ,
Class :
The correct answer is B.

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from ,
Subject :NSO    Class : Class 3

Ans 1: (Master Answer)

from ,
Class :
The correct answer is B.

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from ,
Subject :NSO    Class : Class 5

Ans 1:

abhinav from d a v public school, Angul
Class : Class 5
tell in experiment form

Ans 2:

Sharad Jain from Presidium, Ghaziabad
Class : Class 5
It is option Q because when we heat it up , the solubility increases .

Ans 3:

abhinav from d a v public school, Angul
Class : Class 5

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from ,
Subject :NSO    Class : Class 3

Ans 1:

Ishan Priyadarsi from Euro School, bangalore
Class : Class 6

Ans 2:

Sourish Mahakul from Delhi Public School Electronic City, Bengaluru
Class : Class 8
Option C is correct

Ans 3:

VANSH GARG from DPSG, GHAZIABAD
Class : Class 4
please explain how

Ans 4:

Dhruv Sachdev from Bhavan Vidyalaya, chandigarh
Class : Class 8
ANS IS C

Ans 5:

from ,
Class :
Both North and South have the sunlight from morning to afternoon so maximum time of sunlight. East has only morning and west has only afternoon so they have lesser time

Ans 6:

from ,
Class :
PLEASE EXPLAIN HOW

Ans 7:

Shreya Shruti from Airforce school , Bengaluru
Class : Class 9

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ankitadasgupta from dps, Bengaluru
Subject :NSO    Class : Class 7

Ans 1: (Master Answer)

from ,
Class :
The correct answer is B.

Ans 2:

from ,
Class :

Ans 3:

Keratin from Chrysalis High, Bangalore
Class : Class 8
The correct answer is B. In 4sec the objet increases its speed to 200m/s . Acceleration=(200-0)÷4 = 50m/s^2. S=ut 1/2×at^2. Solve it you'll get 400m. a=acceleration(50), t=time(4), u=initial velocity(0) and s is displacement(consider it distance travelled)

Ans 4:

Arnav Ranka from Gyan Bharati School, Saket, New Delhi
Class : Class 9
How is it 200m? I am getting 800m.

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