Subject :NSO Class : Class 9
Class : Class 9
i think the above explanation is good and would be more accurate if shft of centre of mass is calculated
Class : Class 10
I think it should be 7GM^2/256R^2
G is constant. M will become 7M/8 due to mass removal .M2 will be M/8 . Distance is 2 R . So the product is equivalent to the above. But I don't know how it is not in answers
Class : Class 7
I agree with Gh from Mahatma, Ghaziabad, options are not correctly provided in the question.
Subject :NSO Class : Class 9
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Subject :NSO Class : Class 9
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Subject :NSO Class : Class 9
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Subject :NSO Class : Class 9
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Subject :NSO Class : Class 7
Ans 5:
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Subject :NSO Class : Class 7
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Subject :NSO Class : Class 5
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Subject :NSO Class : Class 5
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Subject :NSO Class : Class 3
After removing some squares from a big square, the following figure is obtained. The length of one side of a small square is 3 cm. Find the area of the figure.