Subject :NSO Class : Class 10
Subject :NSO Class : Class 7
Ans 1:
Class : Class 8
answer should be option a . Baking Soda is used to neutralize forming acid
Ans 2:
Class : Class 9
your answer is wrong baking soda neutralize forming acid
Ans 3:
Class : Class 7
yes
Ans 4:
Class : Class 7
The answer has to be option A
Ans 5:
Class : Class 8
The answer is option A as baking soda neutralizes the effect of the formic acid
Ans 6:
Class : Class 7
yes
Post Your Answer
Subject :NSO Class : Class 9
Post Your Answer
Subject :NSO Class : Class 3
Ans 1:
Class : Class 4
d
Ans 2:
Class : Class 3
D
Post Your Answer
Subject :NSO Class : Class 5
Ans 1:
Class : Class 6
answer option(d)ie H
Ans 2:
Class : Class 5
H
Post Your Answer
Subject :NSO Class : Class 4
Ans 1:
Class : Class 4
B
Ans 2:
Class : Class 3
Ans 3:
Class : Class 5
A
Ans 4:
Class : Class 5
B-green leafy vegetables
Ans 5:
Class : Class 8
A . cereals , potatoes
Ans 6:
Class : Class 3
B
Post Your Answer
Subject :NSO Class : Class 4
Ans 1:
Class : Class 7
Answer is D as both precipitation and condensation are involved in formation of dew in humid nights. The water vapor condenses to form clouds. But, if precipitation was not there, the dew would have remained in the clouds! So, precipitation is also involved in formation of dew on humid nights. Q and R are condensation and precipitation respectively. Thus, the answer is D(condensation and precipitation) and not B(only condensation).
Ans 2:
Class : Class 4
D
Ans 3:
Class : Class 4
D
Post Your Answer
Subject :NSO Class : Class 7
Three similar light bulbs are connected to a constant voltage d.c supply as shown in the diagram. Each
bulb operates at normal brightness and the ammeter
(of negligible resistance) registers a steady current.
The filament of one of the bulbs breaks. What happens
to the ammeter reading and to the brightness of the
remaining bulbs?
| Ammeter reading | Bulb brightness | |
| A | Increase | Increase |
| B | Unchanged | Unchanged |
| C | Decrease | Unchanged |
| D | Decreases | Decreases |
The correct answer should be D because when current decreases,brightness also decreases
Ans 1:
Class : Class 9
Since it is in a parallel circuit, resistance offered is more after one of the bulbs is fused. This will increase the brightness of the bulb but decrease the ammeter reading since current is inversely proportional to resistance
Ans 2:
Class : Class 7
Ans 3:
Class : Class 4
how come??
Post Your Answer
Subject :NSO Class : Class 5
Ans 1:
Class : Class 5
A
Ans 2:
Class : Class 6
non of these as all the options are true
Ans 3:
Class : Class 6
non of these as all the options are true
Post Your Answer
Subject :NSO Class : Class 5
Ans 1:
Class : Class 5
COAL IS NOT BLACK GOLD. ITS BLACK DIAMOND.............PETROLEUM IS NOT BLACK DIAMOND. ITS BLACK GOLD....................................................
Ans 2:
Class : Class 5
D
Ans 3:
Class : Class 6
the answer will be d as all are present in the grid
Ans 4:
Class : Class 3
Ans 5:
Class : Class 5
Ans is B. It is an error. Option B should display-'The main mineral present in this SEDIMENTARY rock is quartz' and the answer to that is Sandstone which is present in the grid
Ans 6:
Class : Class 6
answer is B. the main mineral present in this rock is quartz-sandstone
sandstone can be found in the grid so it is the answer.
