National Science Olympiad Forum By SOF Olympiad Trainer - Page 540
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Anshuman D from MVM, Hyderabad
Subject :NSO    Class : Class 7

Ans 1:

priyanka from kendriya vidalaya kathmandu, JHAJJAR
Class : Class 8
option b

Ans 2:

Anish Ranjan Senapati from V S VIDYALAYA, KORAPUT
Class : Class 5

Ans 3:

priyanka from kendriya vidalaya kathmandu, JHAJJAR
Class : Class 8
option b

Ans 4:

Derek from Arsha vidya Mandir, Chennai
Class : Class 7
It should be destarched first

Ans 5:

KHYATI LAKHCHAURA from MVN, FARIDABAD
Class : Class 8
it should be destarched first then keep the setup in sunlight because if we will directly test the presence of starch both the leaves will show blue -black color as there will be starch already present in both of them. So the correct answer should be OPTION A

Ans 6:

kartick Somasundaram from cps, chennai
Class : Class 3
option B

Ans 7:

Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Class : Class 8
The leaves should be destarched first, so that there is no presence of starch prior to the experiment in any of the leaves. In that manner, the experiment will be more clear. Therefore, Option A is also a potential answer.

Ans 8:

Rohan A Gowda from Jnana Sagara International Public School, Channarayapatna
Class : Class 8
The plant should be destarched first and then used for the experiment To accurately test for the presence of starch in leaves X and Y.

Ans 9:

priyanka from kendriya vidalaya kathmandu, JHAJJAR
Class : Class 8
option b

Ans 10:

Karan Oberoi from Amanora School, Pune
Class : Class 8
Destarching of leaf is a more effective way so option A should be correct

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Ashwak from Cambridge, Jalandhar
Subject :NSO    Class : Class 3

Ans 1:

Yatindra G from SBOA, Chennai
Class : Class 4
B!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Ans 2:

SRIRAM SRINIVASAN PAKU from KENDRIYA VIDHALAYA ASHOK NAGAR, CHENNAI
Class : Class 6

Ans 3:

Haris from Deens academy , Banglore
Class : Class 5
all the questions answer is b

Ans 4:

Haris from Deens academy , Banglore
Class : Class 5
b

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Arnav kaul from Chirec, Hyderabad
Subject :NSO    Class : Class 5

Ans 1:

Shreetej from Pearson public school, Pune
Class : Class 5
d is correct answer

Ans 2: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

Ans 3:

Shubhank Mittal from Lotus Valley International School, Noida
Class : Class 5

Ans 4:

Sanskriti Nagar from Rose Bud Academy, khagaria
Class : Class 5
D

Ans 5:

Shreetej from Pearson public school, Pune
Class : Class 5
D is the answer

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Arnav kaul from Chirec, Hyderabad
Subject :NSO    Class : Class 5

Ans 1:

CHIRAG KHORIA from EVERGREEN PUBLIC SCHOOL, MAYNAGURI
Class : Class 5
tough one,i think the explanation is:S is lens and that part is not colored and t is either eye lids or cornea and neither of them is folded skin.acoording to me

Ans 2:

niuv from meridian, Hyderabad
Class : Class 6

Ans 3:

Mehar from NCS, Vasco
Class : Class 5
please explain

Ans 4:

Soham from DPS Whitefield, Bangalore
Class : Class 4
wrong answer

Ans 5:

Anya the IEO prodigy gymnast from Gopalan International School, Bengaluru
Class : Class 4
very tough though the ans is c

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Arnav kaul from Chirec, Hyderabad
Subject :NSO    Class : Class 5

Ans 1:

Adyasha Senapati from Gopalan International School, Bangalore
Class : Class 6
What's the Correct answer?

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Arnav kaul from Chirec, Hyderabad
Subject :NSO    Class : Class 5

Ans 1:

Dushyant Singh from Shri Ram Centennial School, Indore
Class : Class 6

Ans 2:

Dushyant Singh from Shri Ram Centennial School, Indore
Class : Class 6

Ans 3:

Dushyant Singh from Shri Ram Centennial School, Indore
Class : Class 6

Ans 4:

Dushyant Singh from Shri Ram Centennial School, Indore
Class : Class 6
both answers b and c are not advisable

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Arnav kaul from Chirec, Hyderabad
Subject :NSO    Class : Class 5

Ans 1:

Vallabh Agrawalla from Sai International School, Bhubaneswar
Class : Class 8
After unscrambling the four jumbled words. We get, Sedimentation, Chlorination, Distillation and Filtration. Filtration and Sedimentation are methods of removing insoluble impurities. Distillation is the only option that is used to remove soluble impurities.

Ans 2:

PARUL GHARSE from Vibgyor, Mumbai
Class : Class 6

Ans 3:

Devina kashyap from TPS, Mumbai
Class : Class 4

Ans 4:

Devina kashyap from TPS, Mumbai
Class : Class 4

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shreyash rawat from podar international school, pune
Subject :NSO    Class : Class 4

Ans 1:

Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Class : Class 8
The pattern followed is 6 7=137 9=16So,8 4=12

Ans 2:

Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Class : Class 8
i.e. 6 plus 7 = 13 and 9 plus 7 = 16 . SO, 8 plus 4 is 12.

Ans 3:

Kanav Dhingra from DPS sec45, Gurgaon
Class : Class 10
option B

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Diti Sharma from Amity International School, Noida
Subject :NSO    Class : Class 8

Ans 1:

Arnav Raj Sharma from Dpsvk, Gurgaon
Class : Class 9
Please explain

Ans 2:

Pratyay Anand from Ryan International School, NAVI MUMBAI
Class : Class 9
i dont understand how ?

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Drashti from Global Indian International School, Noida
Subject :NSO    Class : Class 7

Ans 1:

priyanka from kendriya vidalaya kathmandu, JHAJJAR
Class : Class 8
option b

Ans 2:

Ayansh Verma from National Public School ITPL, Bangalore
Class : Class 8

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