Subject :NSO Class : Class 8
Class : Class 9
The answer is B. The water conducts the heat from the iron ball and thus WATER'S temperature will increase while the temperature of the ball will constantly keep decreasing as it is loosing heat. After sometime both the water and the ball come to equilibrium state i.e they have the same temperature. From then on the temperature will remain constant.
AS graph in option B indicates an increase in temperature for a while and then constant temp it is correct
Class : Class 9
The answer is B. The water conducts the heat from the iron ball and thus water's temperature will increase while the temperature of the ball will constantly keep decreasing as it is loosing heat. After sometime both the water and the ball come to equilibrium state i.e they have the same temperature. From then on the temperature will remain constant.
AS graph in option B indicates an increase in temperature for a while and then constant temp It is correct
Subject :NSO Class : Class 8
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Subject :NSO Class : Class 9
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Subject :NSO Class : Class 4
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Subject :NSO Class : Class 4
Ten male animals each of type X and Y were living together for few months in captivity in a well defined area (full of greenery). Other types of animals were not present in this area. Then an animal Z was introduced in this area. After few days, their numbers were counted as shown here.
X | Y | Z |
10 | 2 | 1 |
A Z is a carnivore.
B Y is a herbivore.
C X is a herbivore.
D All of these
Ans 1:
Class : Class 1
The area is full of greenery as mentioned so the herbivore population will increase and as we know carnivores depend on other animals for prey so their population will decrease as they do not eat plants
Ans 6:
Class : Class 8
But then (to continuation of solution) how did number of X animal remain the same?MASTER ANSWER from Revisewise Noida please EXPLAIN.
Ans 9:
Ans 13:
Class : Class 5
IF X AND Y ARE BOTH HARBIVORES THEN WHY DIDNT Z EAT X? SO I THINK X WILL BE CARNIVORE
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Subject :NSO Class : Class 8
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Subject :NSO Class : Class 4