National Science Olympiad Forum By SOF Olympiad Trainer - Page 482

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Subject :NSO    Class : Class 3

Ans 1:

Class : Class 3
your answer is right

Ans 2:

Class : Class 8
C

Ans 3:

Class : Class 3
C

Ans 4:

Class : Class 3
The correct answer is C

Ans 5:

Class : Class 3
how can we send parcels on e-mail

Ans 6:

Class : Class 3
online document so C

Ans 7:

Class : Class 3

Ans 8:

Class : Class 9
The correct answer is C.

Ans 9:

Class : Class 4

Ans 10:

Class : Class 4

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Subject :NSO    Class : Class 7

Ans 1:

Class : Class 9
Apropos to the question the mass of the car has a role in the momentum of the car, as Momentum=mv ,therefore option 'C' should be the correct answer.

Ans 2:

Class : Class 9
No b is only

Ans 3:

Class : Class 8
C should be the correct answer. Same has been explained in the solution also.

Ans 4:

Class : Class 7
if you read the solution properly it is quite clear that the answer is b

Ans 5:

Class : Class 8
c is the correct answer and solution is also given in favour of option c. but answer is b

Ans 6:

Class : Class 5

Ans 7:

Class : Class 9
C only

Ans 8:

Class : Class 9

Ans 9:

Class : Class 4
C is the correct answer. Force is applied to stop the vehicle. The formulae of force is mass * acceleration. Acceleration is final velocity - initial velocity by time. F= M*{(v-u)/t} and its kinetically equation is F=M *[v square - u square/ 2 * distance]. Which ever formula for force has been taken MASS is important. So clearly MASS HAS A ROLE TO PLAY. hence the answer must be C

Ans 10:

Class : Class 9
Yes

Ans 11:

Class : Class 6
Though it looks like mass has no role to play in braking distance, actually coeff of friction (COF) between tyre and road surface has inverse relationship with braking distance. COF depends on normal force due to weight of vehicle and therefore indirectly mass plays a role on braking distance. The correct answer should be C

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Subject :NSO    Class : Class 7

Ans 1:

Class : Class 7
it should be destarched first then keep the setup in sunlight because if we will directly test the presence of starch both the leaves will show blue -black color as there will be starch already present in both of them. So the correct answer should be OPTION A

Ans 2:

Class : Class 8
option b

Ans 3:

Class : Class 5

Ans 4:

Class : Class 8
Destarching of leaf is a more effective way so option A should be correct

Ans 5:

Class : Class 8
option b

Ans 6:

Class : Class 7
It should be destarched first

Ans 7:

Class : Class 1
option B

Ans 8:

Class : Class 8
option b

Ans 9:

Class : Class 8
The leaves should be destarched first, so that there is no presence of starch prior to the experiment in any of the leaves. In that manner, the experiment will be more clear. Therefore, Option A is also a potential answer.

Ans 10:

Class : Class 7
The plant should be destarched first and then used for the experiment To accurately test for the presence of starch in leaves X and Y.

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Subject :NSO    Class : Class 3

Ans 1:

Class : Class 5
b

Ans 2:

Class : Class 4
B!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Ans 3:

Class : Class 6

Ans 4:

Class : Class 5
all the questions answer is b

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Subject :NSO    Class : Class 5

Ans 1:

Class : Class 5
D is the answer

Ans 2:

Class : Class 5
D

Ans 3:

Class : Class 5
d is correct answer

Ans 4: (Master Answer)

Class : Class 1

Ans 5:

Class : Class 5

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Subject :NSO    Class : Class 5

Ans 1:

Class : Class 3
very tough though the ans is c

Ans 2:

Class : Class 4
wrong answer

Ans 3:

Class : Class 5
tough one,i think the explanation is:S is lens and that part is not colored and t is either eye lids or cornea and neither of them is folded skin.acoording to me

Ans 4:

Class : Class 5
please explain

Ans 5:

Class : Class 6

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Subject :NSO    Class : Class 5

Ans 1:

Class : Class 6
What's the Correct answer?

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Subject :NSO    Class : Class 5

Ans 1:

Class : Class 6
both answers b and c are not advisable

Ans 2:

Class : Class 6

Ans 3:

Class : Class 6

Ans 4:

Class : Class 6

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Subject :NSO    Class : Class 5

Ans 1:

Class : Class 4

Ans 2:

Class : Class 4

Ans 3:

Class : Class 6

Ans 4:

Class : Class 8
After unscrambling the four jumbled words. We get, Sedimentation, Chlorination, Distillation and Filtration. Filtration and Sedimentation are methods of removing insoluble impurities. Distillation is the only option that is used to remove soluble impurities.

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Subject :NSO    Class : Class 4

Ans 1:

Class : Class 8
The pattern followed is 6 7=137 9=16So,8 4=12

Ans 2:

Class : Class 10
option B

Ans 3:

Class : Class 8
i.e. 6 plus 7 = 13 and 9 plus 7 = 16 . SO, 8 plus 4 is 12.

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