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Senthil Kumar from Emerald Valley Public school, Salem
Subject :GENERAL    Class : Class 7

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Vivek Kumar Pathak from Aps bolarum, Secunderabad
Subject :GENERAL    Class : Class 9

Ans 1:

Aishwarya Dwivedi from St. John's School, Marhauli, Varanasi
Class : Class 9
Science is a systematic enterprise that deals with the study of universe with the help of predictions and experimental studies.

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Nirabhra from bluebells international, New Delhi
Subject :Sam    Class : Sample

Ans 1:

Aditya kaushik from Delhi Public School Bhilai, Bhilai
Class : Class 9
speed = distance/time

Ans 2:

kashvi from Amity, noida
Class : Class 7
Given .. (1) time taken to take 10 shots=1 sec ==> time taken to take one shot= 1/10 sec (2) Distance travelled by ball while camera took 6 shots =15 meter We know , speed= distance/time Distance=15m Time= Not known... lets find out the time to take six shots Fist shot was taken after = 0sec (as first short was taken at beginning) Second shot taken after = 1*(1/10) = 1/10 seconds Third short taken after = 2*(1/10) =2/10 seconds Similarly .. sixth shot taken after = 5*(1/10) =5/10 Now.. speed = distance/time = 15 / (5/10) = 30 m/second Hope, it helps.

Ans 3:

Aditya from Bvb vidyashram, Jaipur
Class : Class 7
thanks kashvi I now really understand how to solve these type of questions . Very good explanation.

Ans 4:

Chinmay Pathak from Navy Children School, Ernakulam
Class : Class 7
Time taken to shoot 10 images is 1 secTime taken to shoot 6 images is 0.6 sec.Assuming that the full revolution of ball is not considered thenSpeed = distance/time= 15/0.6= 25m/sIf we consider that in five shots the ball has exactly done two revolution then we have to also consider that it has travelled only 12.5 MTS.Then the speed is 12.5/0.5=25 m/s

Ans 5:

itanya from Manav Rachna International School, Ludhiana
Class : Class 7
how to solve this question

Ans 6:

ggggv from british english school, gaya
Class : Class 7
how to solve it?

Ans 7:

Ashwath from Green Park Senior Secondary School , Namakkal
Class : Class 9
How to solve this question

Ans 8:

Agrani from St. Karen's Secondary School, Patna
Class : Class 7
PLEASE TELL THE SOLUTION

Ans 9:

Kashish Kathuria from Vibgyor High, Bangalore
Class : Class 6
kasha and tamana thanks for explanation

Ans 10:

Akhilesh Kancharla from International Educational Academy, Hyderabad
Class : Class 7
a

Ans 11:

MRITTIKA DAS from KENDRIYA VIDYALAYA, GANGTOK, GANGTOK
Class : Class 7

Ans 12:

Nishant Borah from SHRIMANTA SHANKAR ACADEMY, Guwahati
Class : Class 7
ANS NO.6 IS NOT AT ALL CLEAR

Ans 13:

Pulkit Gupta from Maxfort School, New Delhi
Class : Class 7
nice explanation from kashvi and tamanna de

Ans 14:

niketh from dps east, bangalore
Class : Class 6
thank you answer 11 was very clear and understandable

Ans 15:

RAHUL SINHA from D.A.V Public Koyla Nagar Dhanbad, dhanbad
Class : Class 7
Speed=distance /time But the answer is 30 m/s^-1

Ans 16:

tamanna de from K.V.Kailashahar, kailashahar
Class : Class 7
time taken to shoot 10 images=1 second.time taken to shoot 5 images=5/10=1/2seconds.speed=distance/time=15divided by 1/2=15*2=30m/s

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swattik from Niva Ananda Vidyalaya, Kolkata
Subject :Sam    Class : Sample

Ans 1:

Sheetali from Gokhale Memorial Girls School , Kolkata
Class : Class 9

Ans 2:

kd2441971@gmail.com from rlps, Jhansi
Class : Class 9
which logic is used in this question

Ans 3:

Anony from home, Singapore
Class : Class 9
noicedis forum is buggy

Ans 4:

Aditya bubna from St Vincent convent sr sec school, Balasore
Class : Class 9
How the answer come

Ans 5:

sunita arya from ALLEN INSTITUDE, GANGAPUR CITY
Class : Class 9

Ans 6:

Samaksh Mittal from Army Public School Udhampur, Udhampur
Class : Class 9
Very logical ques

Ans 7:

atharva tambat from st.Marys ICSE school,Koparkhairne, Mumbai
Class : Class 9

Ans 8:

BHARATI PRADHAN from ARMY PUBLIC SCHOOL, GUWAHATI
Class : Class 9
Please tell me the logic behind this question......

Ans 9:

Sanjana Thampy from Ncfe, Bangalore
Class : Class 9
how

Ans 10:

BHARATI PRADHAN from ARMY PUBLIC SCHOOL, GUWAHATI
Class : Class 9
I GOT THE LOGIC BEHIND IT.....For example we take ..93 27 63 3now we will subtract 93-27 then we will subtract the difference with 3 ..therefore we get the number 63...The same happens in all the cases..in this question

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Yashas Jain from Sachdeva global school , New Delhi
Subject :Sam    Class : Sample

Ans 1:

Anjaneya Rewade from Gitanjali primary school, Hyderabad
Class : Class 5
please explain

Ans 2:

Bhanu from Ffhjkjj, Hyd
Class : Class 5

Ans 3:

ADITHYA PRASANNA from Delhi Public School, Secunderabad
Class : Class 5
COULD NOT UNDERSTAND

Ans 4:

soham swarup behera from Delhi Public School Ukkunagaram, Visakhapatnam
Class : Class 6

Ans 5:

Shaurya Suryawanshi from The Orbis school, Pune
Class : Class 5
So simple

Ans 6:

Dhawala from SBPPS, Pune
Class : Class 5
so simple for me

Ans 7:

Aniket kumar from kendriya vidyalaya, Delhi
Class : Class 7

Ans 8:

aaryan chandrakant sonawane from nanded city public school, Pune
Class : Class 6

Ans 9:

Aniket kumar from kendriya vidyalaya, Delhi
Class : Class 7
explain anybody

Ans 10:

Saher Gole from IES Orion, MUMBAI
Class : Class 5
CAN SOMEONE EXPLAIN?

Ans 11:

AUMKAR from ST.Xavier International School, Bhubaneswar
Class : Class 5

Ans 12:

Himanish Basu from Army Public School Kamaraj Road, Bangalore
Class : Class 6
I think this shape may not be a rectangle.The question is about how do you see from above.

Ans 13:

Arkoprava Dey from Techno India Group Public School, Coochbehar, Coochbehar
Class : Class 4
the image what you can see from the top of this figure is the answer_____....

Ans 14:

able antony from Indian school muscat, Muscat
Class : Class 5
please explain

Ans 15:

Jayneel from Calorx Olive international school , Ahmedabad
Class : Class 5
Please explain

Ans 16:

Aarush from Podar, Mumbai
Class : Class 7
can you explain

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Shaurya Manjkhola from St Kabir Public School Chandigarh, Chandigarh
Subject :GENERAL    Class : Class 6
z

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Shaurya Manjkhola from St Kabir Public School Chandigarh, Chandigarh
Subject :GENERAL    Class : Class 6
z

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Shaurya Manjkhola from St Kabir Public School Chandigarh, Chandigarh
Subject :GENERAL    Class : Class 6
z

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Shaurya Manjkhola from St Kabir Public School Chandigarh, Chandigarh
Subject :GENERAL    Class : Class 6
z

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Shaurya Manjkhola from St Kabir Public School Chandigarh, Chandigarh
Subject :GENERAL    Class : Class 6
z

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