Option A 84 m is the right answer.
Solution : The area of square is 144 m as given. Hence, the side of square is 12 m. The length of one smaller square in the shaded square is 6 m.
Hence the length of the rectangle is 6+6+6+6 =24
the breadth of rectangle is 6+6+6=18
The perimetre of rectangle is 2(l+b) = 2 (24+18) = 2*42 = 84 m
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Ans 6:
Class : Class 6
IF WE TAKE 1st 4 THEN 5 AND THEN AT LAST 1 THEN IT WILL COME 22 AND PLEASE START COUNTING FROM 13 NOT FROM 11
Ans 7:
Ans 8:
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Ans 8:
Ans 9:
Class : Class 8
250 GRAMS .
FIRST DIVIDE 3200 BY 10 . ANS =320
THEN SUBTRACT 70 FROM 320. ANS =250
WEIGHT OF THE CYLINDER =250
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Ans 1:
Class : Class 4
A- EMI 1970 per month
3 years = 36 months
Total Amount Paid in three years
36 x 1970 = 70920
B - Rajat Paid Advance - 35000
Total Amount Paid
A +B
70920+35000= 105920
Answer is C
Ans 3:
Ans 6:
Class : Class 8
3 years = 36 months, and EMI paid each month= 1970/-, so the total amount paid in EMI is 36 x 1970, which is 70920.
Therefore, total value of the car is 35000 + 70920 = 105920/-.
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Ans 2:
Class : Class 6
actually,they are asking which one has the same relationship as 40 and 70 which is 10 and 40 so, B is the correct answer
Ans 13:
Class : Class 4
The common factors of 40 and 70 are 2,5 and 10 which are same as common factors of 10 and 40. (2,5,10) and hence answer B is correct.
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Ans 1:
Ans 2:
Ans 4:
Class : Class 10
Shilpa_Age = 4* Raj_Age --- (1)
Riya_Age = Raj_Age - 6 --- (2)
Shilpa_Age + Raj_Age + Riya_Age = 72
This can be rewritten as, (from (1) and (2))
4*Raj_Age + Raj_Age + Raj_Age - 6 =72
6*Raj_Age = 78
Raj_Age = 78/6 = 13
Therefore,
Shilpa_Age = 4*13 = 52
Riya_Age = 13 - 6 = 7
Therefore, Shilpa is 52 - 7 = 45 years elder than Riya
Option (B)
Ans 5:
Class : Class 5
The step written by you
4R + R + R - 6 = 72
6R = 66
This step is wrong. As 6 will be added to 72 and NOT SUBTRACTED.
hence, 6R = 78
Ans 6:
Class : Class 10
Answer: D
Solution
Let age of Shilpa, Raj and Riya be S, R, and Ri respectively
Then
S = 4R
Ri = R - 6
S + R + Ri = 72
or
4R + R + R - 6 = 72
6R = 66
R = 11
S = 44
Ri = 5
So Shilpa is (44- 5) 39 years older than Riya
Solution
Let age of Shilpa, Raj and Riya be S, R, and Ri respectively
Then
S = 4R
Ri = R - 6
S + R + Ri = 72
or
4R + R + R - 6 = 72
6R = 66
R = 11
S = 44
Ri = 5
So Shilpa is (44- 5) 39 years older than Riya
Ans 8:
Class : Class 8
Raj's age = x.
x + 4x + ( x - 6 ) = 72,
or 5x + ( x - 6 ) = 72,
or 5x + x - 6 = 72,
or 6x - 6 = 72,
or 6x = 72 + 6,
or 6x = 78
or x = 78/6
or x = 13, so Raj is 13 years old. Shilpa is 13 x 4 = 52 years old. Riya is 13 - 6 = 7 years old. Shilpa is 52 - 7 = 45 years older than Riya, so answer is B.
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Ans 1:
Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Ans 2:
Class : Class 10
Answer : A
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Solution
3,6,12 are three common factors of 36 and 96 which are also multiple of 3.
Hence the answer is 3 numbers.
The questions is 'how many numbers' and not 'which numbers'.
Ans 3:
Class : Class 8
factors of 36 are 1,2,3,4,6,9,12,18,36
factors of 96 are 1,2,3,4,6,8,12,24,32,48,96
common 1,2,3,4,6,12
multiple of 3 - 3,6,12
ans is A
Ans 5:
Class : Class 9
Answer : A Solution 3,6,12 are three common factors of 36 and 96 which are also multiple of 3. Hence the answer is 3 numbers. The questions is 'how many numbers' and not 'which numbers'.

and the total weight of 10
is 3200 g, what is the weight of
?